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jok3333 [9.3K]
4 years ago
14

How do you solve equations of the form ax=b

Mathematics
1 answer:
Sphinxa [80]4 years ago
4 0

You divide each side of the equation by 'a', and you immediately have
the value of 'x' in terms of 'a and 'b'.

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Answer: 4(2x²+9) or i\frac{3\sqrt{2} }{2}

Step-by-step explanation:

To solve the equation by factoring, we want to set the equation to zero. In order to have the equation equal to zero, we want to add both sides by 36.

8x²=-36            [add both sides by 36]

8x²+36=0

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It may seem that 2x²+9 can be factored further, it actually can't. This tells us that the factored form of the equation is 4(2x²+9)=0.

To solve the equation, we want to find the value of x. We already know the graph does not cross the x-axis because the y-intercept or vertex is (0,9).

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x=\sqrt{-\frac{9}{2} } or x=i\frac{3\sqrt{2} }{2}

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61/100 would be sixty-one out of one hundred HOPE IT HELPS :-)
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