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jok3333 [9.3K]
3 years ago
14

How do you solve equations of the form ax=b

Mathematics
1 answer:
Sphinxa [80]3 years ago
4 0

You divide each side of the equation by 'a', and you immediately have
the value of 'x' in terms of 'a and 'b'.

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A square has an area of 64 m². What is the length of each side?
anygoal [31]

Answer:

8m

Step-by-step explanation:

The area of a square is length*width.

We can square root the area to get the length of each side. Since the shape is a <em>square</em>, the lengths are the same.

\sqrt{64}=8

One side is <u>8m</u>.

7 0
3 years ago
Which expression is equivalent to<br> (6x-9x) - (2x - 3)?
NikAS [45]

Answer:

6x^2 -9x  -2x-3

6x^2 -11x +3

Step-by-step explanation:

7 0
3 years ago
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Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
Find the measure of each angle indicated.
OLga [1]

Answer:

51

Step-by-step explanation:

See the other answer

6 0
3 years ago
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My name is Ann [436]

Answer:

what does it say.........................

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