Answer:
1) k = 3
2) 3, 4, 5
3) k + (k + 2) + (k + 4) = 4k
4) 6, 8, 10
Step-by-step explanation:
Jared used the equation;
k + (k + 1) + (k + 2) = 4k
Let's find k.
3k + 3 = 4k
4k - 3k = 3
k = 3
Thus,the integers will be;
3, (3 + 1) and (3 + 2)
This is; 3, 4, 5
He is looking for consecutive even integers but yet got 3 and 5 which are odd numbers. However, he should have used the format;
k, (k + 2), (k + 4) as the 3 consecutive even integers.
Thus, rewriting the main equation gives;
k + k + 2 + k + 4 = 4k
3k + 6 = 4k
4k - 3k = 6
k = 6
Thus,the integers are;
6, (6 + 2), (6 + 4)
This is; 6, 8, 10
Answer:
121
Step-by-step explanation:
You are missing a parentheses
Assuming you just mean to close the parentheses
((5-(-4)^2)^2)
The first step is to complete the inside parentheses
PEMDAS
(5-(-4)^2)
Do the exponents first
(5-(16))
-11
Put this in the equation for (5-(-4)^2)
(-11) ^2
121
Answer:
zero point zero zero one two five
Step-by-step explanation:
Find the difference between the existing terms:
-8 / -4 = 2
-16/-8 = 2
This means the next term is the previous term multiplied by 2:
The first term is given as -4
You would start with the first term ( -4) then multiply it by the difference of terms ( 2) raised to the nth term (n) minus 1.
An = -4 * 2^n-1
The answer is A
