All categories

3 years ago

Which description matches with which graph?

Physics

1 answer:

VikaD [51]3 years ago

4 0

Answer:

Description 1 matches C.

Description 2 matches A.

Description 3 matches D.

Description 4 matches B.

Explanation:

Description 1 matches C. From graph C, we can see that the distance remains constant at a particular value. Hence, the car is not traveling and hence it is stopped.

Description 2 matches A. Speed is determined by the gradient of a distance-time graph. A depicts a linear graph which tells us that the gradient is constant and hence the car is at constant speed. The fact that the distance is increasing shows that the car is moving forward.

Description 3 matches D. Graph of D becomes less steeper as time progresses. This tells us that the gradient of the graph is decreasing and hence the speed of the car is decreasing.

Description 4 matches B. Graph B shows distance being decreased. This tells us that the car is coming back.

You might be interested in

Question 7

erastova [34]

gdj dhbdh sbctcrxrxvh7sdchhcsh

4 0

3 years ago

If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?

Aliun [14]

Answer:

F = G Newtons

Explanation:

Given:

Mass of 1st body = $1\:kg$
Mass of 2nd body = $4\:kg$

To Find:

Magnitude of gravitational force

Solution:

Here, we have a formula

$F=\dfrac{G.M_{1}.M_{2}}{r^{2}}$

Substituting the values

$\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}$

$\implies\:\:F = \dfrac{4G}{4}$

$\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}$

$\implies\:\:\red{F = G}$

Know More:

The applied formula for the above solution is

${\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}$

where,

F $_{G}$ = Gravitational force
G = Gravitational constant
M $_{1}$ = mass of 1st body
M $_{2}$ = mass of 2nd body
r = distance between two bodies

6 0

3 years ago

The primary purpose of describing planetary orbits in terms of epicycles and deferents was to account for the

dexar [7]

Retrograde. Planets seem to move forward and then backward sometimes. This is really because we pass them as we move in our orbit but astronomers wanted to try to describe the solar system with earth at the center so elaborate models were employed.

3 0

4 years ago

A force of 40N is applied to a 28 g mass, what is the acceleration? (round to the hundredths place)

Leno4ka [110]

Answer:

1428.6m/s²

Explanation:

Given parameters:

Force applied on the body = 40N

Mass of the body = 28g

1000g = 1kg

28g will therefore be 0.028kg

Unknown:

Acceleration = ?

Solution:

To solve this problem, we use the expression derived from Newton's second law of motion.

Force = mass x acceleration

Insert the parameters and solve;

40 = 0.028 x acceleration

Acceleration = $\frac{40}{0.028}$ = 1428.6m/s²

7 0

3 years ago

Bacteria can move by all of the following ways except:

Mrac [35]

Answer:

what r the options that are there

Explanation:

6 0

3 years ago