Factors that affect heat transfer are:
1) Difference in temperature,
2) Mass of the object
3) Specific heat of the object
Hope this helps!
Answer:
v₂ = 70 m / s
Explanation:
For this exercise let's use Bernoulli's equation
where subscript 1 is for the top of the mountain and subscript 2 is for Tuesday's level
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ +1/2 ρ v₂² + ρ g y₂
indicate that the pressure in the two points is the same, y₁ = 250 m, y₂ = 0 m, the water in the upper part, because it is a reservoir, is very large for which the velocity is very small, we will approximate it to 0 (v₁ = 0), we substitute
ρ g y₁ = ½ ρ v₂²
v₂ =
let's calculate
v₂ = √( 2 9.8 250)
v₂ = 70 m / s
Answer:
fly......................
Well first graph represents rectangular hyperbola
vu = c^2 ( c is constant)
AS 1/v + 1/u = 1/f
Take1/ f to be constant c
1/v = c - 1/u
it is of the form y = - x + k
Slope = -1 having intercept k as shown in fig 2