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3 years ago

If m∠A = (3x-6)° and m∠B = (x + 9)°, find the m∠D.

Mathematics

1 answer:

jeyben [28]3 years ago

7 0

Because line BD goes through the center of the circle Angle A is a right angle which equals 90 degrees.

Set the equation for A to equal 90 and solve for x:

3x-6 = 90

Add 6 to each side:

3x = 96

Divide both sides by 3:

x = 32

Now we have a value for x , use that to solve for angle b:

B = x +9 = 32 + 9 = 41 degrees.

Now we know A and B, we can solve for D.

The three inside angles of a triangle need to equal 180.

D = 180 - 90 - 41 = 49 degrees.

The answer is D) 49

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Angela’s grandfather gave her all the cash he had in his pocket to buy raffle tickets that cost $1

daser333 [38]

In this problem situation:

the independent quantity is the money Angela's grandfather gave her
the dependent quantity is the number of raffle ticket Angela will buy.

An independent quantity is the quantity that affects or brings a change in a dependent quantity.

The dependent quantity is affected by the independent quantity. If the independent quantity changes, the dependent quantity will change.

The dependent quantity is dependent on the independent quantity.

Let's relate it to the problem situation:

The amount of money Angela's grandfather gave her is unknown, therefore, the number of raffle tickets Angela can buy cannot be ascertain.

If we know how much Angela's grandfather gave her, we can determine how many raffle tickets Angela can buy.

This implies that the number of raffle ticket Angela will buy is dependent on how much money her grandfather gave her.

Therefore, in this problem situation:

the independent quantity is the money Angela's grandfather gave her
the dependent quantity is the number of raffle ticket Angela will buy.

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brainly.com/question/19967540

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2 years ago

Which polygons are congruent? Select each correct answer.

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3 years ago

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Are they all correct ? And help with the number 4 please ? Thank you

nirvana33 [79]

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3 years ago

Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81

Anton [14]

Using Lagrange multipliers, we have the Lagrangian

$L(x,y,z,\lambda)=x+y-z+\lambda(x^2+y^2+z^2-81)$

with partial derivatives (set equal to 0)

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$
$L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}$
$L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}$
$L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81$

Substituting the first three equations into the fourth allows us to solve for $\lambda$ :

$x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}$

For each possible value of $\lambda$ , we get two corresponding critical points at $(\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3)$ .

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Illusion [34]

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