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Gwar [14]
3 years ago
12

What type of angle is formed when the radius and a tangent intersect at the points of tangency?

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

ANSWER

A. Right

EXPLANATION

A tangent to a circle touches the circle at only one point.

The point where a tangent and a radius meet at is called the point of tangency.

The tangent to a circle meets the radius of a circle at a right angle.

This is because the angle between the tangent and the radius of the circle is 90°

The correct answer is A.

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Amy is going on a 4 1/4 mile hike She has already hiked 2 3/4 miles. How many more miles does she have left to hike?
babymother [125]

Answer:

2 1/4 left to hike

Step-by-step explanation:

2+2=4         3+1=4

5 0
3 years ago
Samantha is looking to determine the amount of interest that she will pay on her 4.7% , $40,000 loan over its 15 -year term. The
AysviL [449]

Answer:

The total amount of interest Samantha will pay=$40,842.47

Step-by-step explanation:

Step 1: Determine expression of total interest amount to be payed

The expression for the total interest amount to be payed inclusive of interest is given by;

A=P(1+r/n)^(nt)-P

where;

A=total amount of interest to be payed

P=principal loan amount

r=annual interest rate

n=number of compounding periods in a year

t=number of years

In our case;

P=$40,000

r=4.7%=4.7/100=0.047

n=12

t=15 years

replacing;

A=40,000(1+0.047/12)^(12×15)-40,000

A=40,000(1.00392)^180-40,000

A=40,842.46821

The amount rounded of to the nearest cents=1/100=0.01, round off to the nearest 2 decimal places=40,842.47

The total amount of interest Samantha will pay=$40,842.47

3 0
4 years ago
19) Given that f(x)x² - 8x+ 15x² - 25find the horizontal and vertical asymptotes using the limits of the function.A) No Vertical
Tems11 [23]

EXPLANATION

Since we have the function:

f(x)=\frac{x^2-8x+15}{x^2}

Vertical asymptotes:

For\:rational\:functions,\:the\:vertical\:asymptotes\:are\:the\:undefined\:points,\:also\:known\:as\:the\:zeros\:of\:the\:denominator,\:of\:the\:simplified\:function.

Taking the denominator and comparing to zero:

x+5=0

The following points are undefined:

x=-5

Therefore, the vertical asymptote is at x=-5

Horizontal asymptotes:

\mathrm{If\:denominator's\:degree\:>\:numerator's\:degree,\:the\:horizontal\:asymptote\:is\:the\:x-axis:}\:y=0.If\:numerator's\:degree\:=\:1\:+\:denominator's\:degree,\:the\:asymptote\:is\:a\:slant\:asymptote\:of\:the\:form:\:y=mx+b.If\:the\:degrees\:are\:equal,\:the\:asymptote\:is:\:y=\frac{numerator's\:leading\:coefficient}{denominator's\:leading\:coefficient}\mathrm{If\:numerator's\:degree\:>\:1\:+\:denominator's\:degree,\:there\:is\:no\:horizontal\:asymptote.}\mathrm{The\:degree\:of\:the\:numerator}=1.\:\mathrm{The\:degree\:of\:the\:denominator}=1\mathrm{The\:degrees\:are\:equal,\:the\:asymptote\:is:}\:y=\frac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}\mathrm{Numerator's\:leading\:coefficient}=1,\:\mathrm{Denominator's\:leading\:coefficient}=1y=\frac{1}{1}\mathrm{The\:horizontal\:asymptote\:is:}y=1

In conclusion:

\mathrm{Vertical}\text{ asymptotes}:\:x=-5,\:\mathrm{Horizontal}\text{ asymptotes}:\:y=1

4 0
2 years ago
--(4+h) = 3h<br> What is H
butalik [34]
H= -1

Distribute:

-(4+h)= -4 - h

-4 - h= 3h

-4 +h = 3h + h

-4= 4h

-1 = h
7 0
3 years ago
Jessica is playing a game where there are 4 blue markers and 6 red markers in a box. She is going to pick 3
Andru [333]

Answer:

The probability of Jessica picking 3 consecutive red markers is: (1/6)

The probability of Jessica's first marker being red, but not picking 3 consecutive red markers is:

(3/5)−(1/6)=(13/30)

So i am bit stuck here

what i think is it shouldn't be that complex it should be as simple as chance of Jessica's first marker being red=chance of getting red 1 time i.e P(First marker being red)=(6/10) can any explain me the probability of Jessica's first marker being red=(13/30)?

Step-by-step explanation:

5 0
3 years ago
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