Answer:
Explanation:
Word equation:
sulfuric acid + ammonium hydroxide → ammonium sulfate + water
Chemical equation:
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
Balanced chemical equation:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.
Steps to balance the equation:
Steps 1;
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
H = 7 H = 10
S = 1 S = 1
O = 5 O = 5
N = 1 N = 2
Step 2:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O
H = 12 H = 10
S = 1 S = 1
O = 6 O = 5
N = 2 N = 2
Step 3:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
H = 12 H = 12
S = 1 S = 1
O = 6 O = 6
N = 2 N = 2
<u>Answer:</u> The equation to calculate the mass of remaining isotope is ![[A]=\frac{20}{10^{-0.217t}}](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B20%7D%7B10%5E%7B-0.217t%7D%7D)
<u>Explanation:</u>
The equation used to calculate rate constant from given half life for first order kinetics:

where,
= half life of the reaction = 
Putting values in above equation, we get:

Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process
= initial amount of the sample = 20 grams
[A] = amount left after decay process = ? grams
Putting values in above equation, we get:
![0.5=\frac{2.303}{t}\log\frac{20}{[A]}](https://tex.z-dn.net/?f=0.5%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B20%7D%7B%5BA%5D%7D)
![[A]=\frac{20}{10^{-0.217t}}](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B20%7D%7B10%5E%7B-0.217t%7D%7D)
Hence, the equation to calculate the mass of remaining isotope is ![[A]=\frac{20}{10^{-0.217t}}](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B20%7D%7B10%5E%7B-0.217t%7D%7D)
Dilution<span> is when you decrease the concentration of a </span>solution<span> by adding a solvent. As a result, if you want to </span>dilute<span> salt water, just add water. ... Add more solute until it quits dissolving. That point at which a solute quits dissolving is the point at which it's </span>saturated<span>.</span>
Answer:

Explanation:
Hello,
In this case, the first step is to compute the number of moles of potassium phosphate in 20.0 mL (0.020L) of the 0.015-M (mol/L) solution as shown below:

Thus, these moles correspond to potassium phosphate moles, which molecular formula is K₃PO₄, therefore, one mole of this compound contains three moles of potassium ions as it has three as its subscript in the formula. Thereby, the moles of potassium ions result in:

Best regards.