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Margarita [4]
3 years ago
9

Which of these molecules has an overall dipole moment? O A. F2 B. H2S C. CH4 D. CO2​

Chemistry
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:

i think the answer is B cus i think of that

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A 0.08541 g sample of gas occupies 10.0-ml at 288.5 k and 1.10 atm. upon further analysis, the compound is found to be 13.068% c
topjm [15]
<span>C2Br2 First, we need to determine how many moles of the gas we have. For that, we'll use the Ideal Gas Law which is PV = nRT where P = pressure (1.10 atm = 111458 Pa) V = volume (10.0 ml = 0.0000100 m^3) n = number of moles R = Ideal gas constant (8.3144598 (m^3 Pa)/(K mol) ) T = Absolute temperature Solving for n, we get PV/(RT) = n Now substituting our known values into the formula. (111458 Pa * 0.0000100 m^3) / (288.5 K * 8.3144598 (m^3 Pa)/(K mol)) = (1.11458/2398.721652) mol = 0.000464656 mol Now let's calculate the empirical formula for this compound. Atomic weight carbon = 12.0107 Atomic weight bromine = 79.904 Relative moles carbon = 13.068 / 12.0107 = 1.08802984 Relative moles bromine = 86.932 / 79.904 = 1.087955547 So the relative number of atoms of the two elements is 1.08802984 : 1.087955547 After dividing all numbers by the smallest, the ratio becomes 1.000068287 : 1 Which is close enough to 1:1 for me to consider the empirical formula to be CBr Now calculate the molar mass of CBr 12.0107 + 79.904 = 91.9147 Finally, let's determine if the compound is actually CBr, or something like C2Br2, or some other multiple. Using the molar mass of CBr, multiply by the number of moles and see if the result matches the mass of the gas. So 91.9147 g/mol * 0.000464656 mol = 0.042708701 g 0.0427087 g is a lot smaller than 0.08541 g. So the compound isn't exactly CBr. Let's divide them to see what the factor is. 0.08541 / 0.0427087 = 1.99982673 1.99982673 is close enough to 2 to within the number of significant digits we have for me to claim that the formula for the unknown gas isn't CBr, but instead is C2Br2.</span>
3 0
3 years ago
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The table below shows the number of sub-atomic particles in an atom of sodium. Sub-atomic Particles Sub-atomic Particle Number P
AlexFokin [52]

Answer is: the amu of a sodium atom is 23.

The unified atomic mass unit (amu) is a standard unit of atom mass.

One unified atomic mass unit is approximately the mass of one nucleon (proton or neutron).

The unified atomic mass unit is equal 1.66·10⁻²⁷ kg.

n(p⁺) = 11; number of protons in sodium atom.

n(n°) = 12; number of neutrons of sodium atom.

n(p⁺ + n°) = 11 + 12.

n(p⁺ + n°) = 23; number of nucleons in sodium atom.

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3 years ago
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Identify the sentence that correctly uses an ellipsis.
zloy xaker [14]
C)"his refusal to cooperate with the police and name the culprit...resulted in his arrest..."
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4 years ago
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What is an indication that a lake is healthy?
N76 [4]

Answer:

D

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As bioindicators are the organism that indicate or monitor the health of the environment

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3 years ago
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The elements of which group are nonreactive?
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The elements of the "Noble" gases group is nonreactive. The reason for this is that noble gases are always or most of the time at room temperature.<span />
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