Explanation:
Bond order is inversely proportional to the bond length.
In 
molecule. one nitrogen is double bonded to nitrogen and one oxygen is single bonded to nitrogen and hydrogen bond.
- Bond order between the (N=O) bond is 2 which means that bond length between the (N=O) bond is shorter than that of the N-O bond.
- Bond order between the (N-O) bond is 1 which means that bond length of the N-O bond is longer than that of the bond length of (N=O) bond.
Density = mass/volume = 800/200 =4 g/cm^3
Answer:
<h2>
0.50 m/s</h2><h2>
</h2>
Explanation:
Velocity = distance over time
where distance = 5.20 m
time = 10.4 s.
velocity = <u> 5.20 m </u>
10.4 s.
= 0.50 m/s
According to the question:
Given,
= 250mg 75mg 375mg
= 5Cc X 250 X
= X = 1.5ml
= 1.5ml/dose X 4 doses/daily X 10 days = 60 ml
<h3>What do you know about amoxicillin?</h3>
Numerous bacterial infections can be treated with amoxicillin. This drug is an antibiotic similar to penicillin. It acts by preventing bacterial development. Only bacterial illnesses are treated by this antibiotic. For viral infections, it is ineffective (such as common cold, flu). Any antibiotic that is overused may stop working to treat subsequent illnesses. Along with other drugs, amoxicillin is also used to treat and prevent the recurrence of stomach / intestinal ulcers brought on by the bacteria H. pylori. Take this medication by mouth every 8 to 12 hours, generally with or without food, as prescribed by your doctor. Your medical condition and treatment response will determine the dosage.
To know more about Amoxicillin, visit:
<u>brainly.com/question/14445732</u>
#SPJ4.
<u>Answer:</u> The mass of second isotope of indium is 114.904 amu
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the mass of isotope 2 of indium be 'x'
Mass of isotope 1 = 112.904 amu
Percentage abundance of isotope 1 = 4.28 %
Fractional abundance of isotope 1 = 0.0428
Mass of isotope 2 = x amu
Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %
Fractional abundance of isotope 2 = 0.9572
Average atomic mass of indium = 114.818 amu
Putting values in equation 1, we get:
![114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu](https://tex.z-dn.net/?f=114.818%3D%5B%28112.904%5Ctimes%200.0428%29%2B%28x%5Ctimes%200.9572%29%5D%5C%5C%5C%5Cx%3D114.904amu)
Hence, the mass of second isotope of indium is 114.904 amu
