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3 years ago

11

Describe a laboratory procedure that can be used to recover the solid solute from the aqueous solution.

1 answer:

erastovalidia [21]3 years ago

5 0

A solid solute can be recovered from a solution by evaporating the solvent completely.

This can be done by heating the solution appropriately. Heating a solution with organic solutes such as sugar will most likely destroy the solute so it's best to let the solution stand in an open area and let it evaporate by itself. However, if you have an inorganic solute such as salt (NaCl), you can completely boil out the water without any problem.

Also, in a research laboratory, a rotary evaporator is commonly used. This instrument employs the principle of vacuum distillation and is used in mainly in removing solvents in solutions.

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Read 2 more answers

Caed for this question.

OLga [1]

Answer:

0.962 atm.

97.4 kPa.

731 torr.

14.1 psi.

97,434.6 Pa.

Explanation:

Hello.

In this case, given the available factors equaling 1 atm of pressure, each required pressure turns out:

- Atmospheres: 1 atm = 760 mmHg:

$p=731mmHg*\frac{1atm}{760mmHg} =0.962atm$

- Kilopascals:: 101.3 kPa = 760 mmHg:

$p=731mmHg*\frac{101.3kPa}{760mmHg} =97.4kPa$

- Torrs: 760 torr = 760 mmHg:

$p=731mmHg*\frac{760 torr}{760mmHg} =731 torr$

- Pounds per square inch: 14.69 psi = 760 mmHg:

$p=731mmHg*\frac{14.69}{760mmHg} =14.1psi$

- Pascals: 101300 Pa = 760 mmHg:

$p=731mmHg*\frac{101300Pa}{760mmHg} \\\\p=97,434.6Pa$

Best regards.

5 0

3 years ago

A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem

Leto [7]

Answer : The final temperature of the copper is, $87.29^oC$

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat gained = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = $0.0923cal/g^oC$

$\Delta T=\text{Change in temperature}$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25^oC$

Now put all the given values in the above formula, we get the final temperature of copper.

$299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)$

$T_{final}=87.29^oC$

Therefore, the final temperature of the copper is, $87.29^oC$

4 0

4 years ago