Answer:
It will cost $68,620.5 to the club to add the grass turf to their field.
Explanation:
length of the field = l = 0.102 km = 0.102 × 1000 m
( 1km = 1000 m)
Width of the field w = 0.069 km = 0.069 × 1000 m
Area of the field , A= l × w
Cost of grass turfing =
Cost of grass turfing on field of :
It will cost $68,620.5 to the club to add the grass turf to their field.
Explanation:
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
Hence, calculate the molarity of given solution as follows.
Molarity of citric acid =
=
= 0.173 M
As citric acid is a triprotic acid so, upon dissociation it gives three hydrogen ions.
Normality = Molarity × no. of hydrogen or hydroxide ions
= 0.173 × 3
= 0.519 N
Thus, we can conclude that molarity of given solution is 0.173 and its normality is 0.519 N.