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masya89 [10]
3 years ago
6

the perimeter of a rectangle is 15x+17y if the length is 7/2x+7y then find the width of the rectangle

Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0

9514 1404 393

Answer:

  4x +3/2y

Step-by-step explanation:

The perimeter is twice the sum of length and width. We can use this to find the width.

  P = 2(L+W)

  15x +17y = 2(7/2x +7y +W)

  15x +17y = 7x +14y +2W . . . . . . eliminate parentheses

  8x +3y = 2W . . . . . . . . . . . . . . . subtract 7x +14y

  W = 4x +3/2y . . . . . . . divide by 2

The width of the rectangle is 4x +3/2y.

Afina-wow [57]3 years ago
3 0

Answer:

w = 4x + 3/2y

Step-by-step explanation:

Perimeter of a Rectangle: P = 2w + 2l

Step 1: Define

P = 15x + 17y

l = 7/2x + 7y

w = unknown

Step 2: Solve for <em>w</em>

  1. <u>Substitute:</u> 15x + 17y = 2w + 2(7/2x + 7y)
  2. <u>Distribute 2:</u> 15x + 17y = 2w + 7x + 14y
  3. <u>Subtract 7x on both sides:</u> 8x + 17y = 2w + 14y
  4. <u>Subtract 14y on both sides:</u> 8x + 3y = 2w
  5. <u>Divide both sides by 2:</u> 4x + 3/2y = w
  6. <u>Rewrite:</u> w = 4x + 3/2y
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