the perimeter of a rectangle is 15x+17y if the length is 7/2x+7y then find the width of the rectangle
2 answers:
9514 1404 393
Answer:
4x +3/2y
Step-by-step explanation:
The perimeter is twice the sum of length and width. We can use this to find the width.
P = 2(L+W)
15x +17y = 2(7/2x +7y +W)
15x +17y = 7x +14y +2W . . . . . . eliminate parentheses
8x +3y = 2W . . . . . . . . . . . . . . . subtract 7x +14y
W = 4x +3/2y . . . . . . . divide by 2
The width of the rectangle is 4x +3/2y.
Answer:
w = 4x + 3/2y
Step-by-step explanation:
Perimeter of a Rectangle: P = 2w + 2l
Step 1: Define
P = 15x + 17y
l = 7/2x + 7y
w = unknown
Step 2: Solve for <em>w</em>
- <u>Substitute:</u> 15x + 17y = 2w + 2(7/2x + 7y)
- <u>Distribute 2:</u> 15x + 17y = 2w + 7x + 14y
- <u>Subtract 7x on both sides:</u> 8x + 17y = 2w + 14y
- <u>Subtract 14y on both sides:</u> 8x + 3y = 2w
- <u>Divide both sides by 2:</u> 4x + 3/2y = w
- <u>Rewrite:</u> w = 4x + 3/2y
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