Answer:
MAOP Master of Arts in Organizational Psychology (various universities)
MAOP Maximum Allowable Operating Pressure
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MAOP Master Air Operations Planner
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Explanation:
Answer:
2.83 kg
Explanation:
Given:
Volume, V = 0.8 m³
gage pressure, P = 200 kPa
Absolute pressure = gage pressure + Atmospheric pressure
= 200 + 101 = 301 kPa = 301 × 10³ N/m²
Temperature, T = 23° C = 23 + 273 = 296 K
Now,
From the ideal gas equation
PV = mRT
Where,
m is the mass
R is the ideal gas constant = 287 J/Kg K. (for air)
thus,
301 × 10³ × 0.8 = m × 287 × 296
or
m = 2.83 kg
Answer:
the practice of exchanging things with others for mutual benefit, especially privileges granted by one country or organization to another.
HOPE THIS HELPED!!!!!!!!!!!!! XDDDDDD
Answer:
Re=100,000⇒Q=275.25 
Re=500,000⇒Q=1,757.77
Re=1,000,000⇒Q=3060.36 
Explanation:
Given:
For air
=25°C ,V=8 m/s
For surface
=179°C
L=2.75 m ,b=3 m
We know that for flat plate
⇒Laminar flow
⇒Turbulent flow
<u> Take Re=100,000:</u>
So this is case of laminar flow

From standard air property table at 25°C
Pr= is 0.71 ,K=26.24
So 
Nu=187.32 (
)
187.32=
⇒h=1.78
heat transfer rate =h
=275.25 
<u> Take Re=500,000:</u>
So this is case of turbulent flow


Nu=1196.18 ⇒h=11.14 
heat transfer rate =h
=11.14(179-25)
= 1,757.77
<u> Take Re=1,000,000:</u>
So this is case of turbulent flow


Nu=2082.6 ⇒h=19.87 
heat transfer rate =h
=19.87(179-25)
= 3060.36 