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alexdok [17]
3 years ago
8

Which of the following circumstances call for a greater than normal following distance?

Engineering
1 answer:
mariarad [96]3 years ago
7 0

Explanation:

The three-second rule is recommended for passenger vehicles during ideal road and weather conditions. Slow down and increase your following distance even more during adverse weather conditions or when visibility is reduced. Also increase your following distance if you are driving a larger vehicle or towing a trailer.

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The sticker inside the door of my car says that the tire pressure should be 32 psig (322 kPa) when the tire is cold. Before a ro
Neko [114]

Answer:

37 psi

Explanation:

For ideal gases this equation applies:

p1*V1/T1 = p2*V2/T2

Since we are assuming volume remains constant:

V2 = V1

p1/T1 = p2/T2

p2 = p1*T2/T1

The temperatures must be in absolute scale.

T1 = 15 + 273  = 288 K

T2 = 60 + 273 = 333 K

Then:

p2 = 32 * 333 / 288 = 37 psi

7 0
3 years ago
Air is to be compressed so that its volume is reduced to half of its original volume if the initial pressure is 200 kPa and the
Alex_Xolod [135]

Answer:

P_{2} = 527.803\,kPa

Explanation:

The politropic relationship for a isentropic process is:

\frac{P_{2}}{P_{1}} = \left(\frac{V_{1}}{V_{2}}  \right)^{\gamma}

Where \gamma is the ratio of specific heats

The final pressure is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}}\right)^{\gamma}

P_{2} = (200\,kPa)\cdot (2)^{1.4}

P_{2} = 527.803\,kPa

7 0
3 years ago
Write a matrix, that is a lower triangular matrix.
shepuryov [24]

Answer:

\left[\begin{array}{ccc}10&0&0\\14&25&0\\57&18&39\end{array}\right]

Explanation:

A lower triangular matrix is one whose elements above the main diagonal are zero meanwhile all the main diagonals elements and below are nonzero elements. This is one of  the two existing types of triangular matrixes. Attached you will find a image referring more about triangular matrixes.

If there is any question, just let me know.

6 0
4 years ago
A sports car has a drag coefficient of 0.29 and a frontal area of 20 ft2, and is travelling at a speed of 120 mi/hour. How much
Andrej [43]

Answer:

Power required to overcome aerodynamic drag is 50.971 KW

Explanation:

For explanation see the picture attached

4 0
3 years ago
Answer true or false 3.Individual people decide what will be produced in a command<br> oconomy
Pie

Answer:

False

Explanation:

The government decides the productions.

7 0
4 years ago
Read 2 more answers
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