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Dimas [21]
4 years ago
14

What is reciprocity?

Engineering
2 answers:
Murrr4er [49]4 years ago
7 0

Answer:

the practice of exchanging things with others for mutual benefit, especially privileges granted by one country or organization to another.

HOPE THIS HELPED!!!!!!!!!!!!! XDDDDDD

alexandr1967 [171]4 years ago
3 0

Answer:

In linear systems is the principle that a response Rab, measured at a location (and direction if applicable). A, when the system has an excitation signal applied at a location (and direction if applicable), B, is exactly equal to Rba which is the response at location b, when that same excitation is applied at a.  This applies for all frequencies of the excitation signal.

Explanation:

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You are investigating surface hardening in iron using nitrogen gas. Two 5 mm thick slabs of iron are separately exposed to nitro
Luden [163]

Answer and Explanation:

The explanation is attached below

4 0
3 years ago
Under normal operating conditions, the electric motor exerts a torque of 2.8 kN-m.on shaft AB. Knowing that each shaft is solid,
77julia77 [94]

Answer:

Explanation:

The image attached to the question is shown in the first diagram below.

From the diagram given ; we can deduce a free body diagram which will aid us in solving the question.

IF we take a look at the second diagram attached below ; we will have a clear understanding of what the free body diagram of the system looks like :

From the diagram; we can determine the length of BC by using pyhtagoras theorem;

SO;

L_{BC}^2 =  L_{AB}^2 + L_{AC}^2

L_{BC}^2 = (3.5+2.5)^2+ 4^2

L_{BC}= \sqrt{(6)^2+ 4^2}

L_{BC}= \sqrt{36+ 16}

L_{BC}= \sqrt{52}

L_{BC}= 7.2111 \ m

The cross -sectional of the cable is calculated by the formula :

A = \dfrac{\pi}{4}d^2

where d = 4mm

A = \dfrac{\pi}{4}(4 \ mm * \dfrac{1 \ m}{1000 \ mm})^2

A = 1.26 × 10⁻⁵ m²

However, looking at the maximum deflection  in length \delta ; we can calculate for the force F_{BC by using the formula:

\delta = \dfrac{F_{BC}L_{BC}}{AE}

F_{BC} = \dfrac{ AE \ \delta}{L_{BC}}

where ;

E = modulus elasticity

L_{BC} = length of the cable

Replacing 1.26 × 10⁻⁵ m² for A; 200 × 10⁹ Pa for E ; 7.2111 m for L_{BC} and 0.006 m for \delta ; we have:

F_{BC} = \dfrac{1.26*10^{-5}*200*10^9*0.006}{7.2111}

F_{BC} = 2096.76 \ N \\ \\ F_{BC} = 2.09676 \ kN     ---- (1)

Similarly; we can determine the force F_{BC} using the allowable  maximum stress; we have the following relation,

\sigma = \dfrac{F_{BC}}{A}

{F_{BC}}= {A}*\sigma

where;

\sigma = maximum allowable stress

Replacing 190 × 10⁶ Pa for \sigma ; we have :

{F_{BC}}= 1.26*10^{-5} * 190*10^{6} \\ \\ {F_{BC}}=2394 \ N \\ \\ {F_{BC}}= 2.394 \  kN     ------ (2)

Comparing (1) and  (2)

The magnitude of the force F_{BC} = 2.09676 \ kN since the elongation of the cable should not exceed 6mm

Finally applying the moment equilibrium condition about point A

\sum M_A = 0

3.5 P - (6) ( \dfrac{4}{7.2111}F_{BC}) = 0

3.5 P - 3.328 F_{BC} = 0

3.5 P = 3.328 F_{BC}

3.5 P = 3.328 *2.09676 \  kN

P =\dfrac{ 3.328 *2.09676 \  kN}{3.5 }

P = 1.9937 kN

Hence; the maximum load P that can be applied is 1.9937 kN

4 0
3 years ago
The files provided in the code editor to the right contain syntax and/or logic errors. In each case, determine and fix the probl
Yanka [14]

Question Continuation

public class DebugOne3{

public static void main(String args){

System.out.print1n("Over the river");

System.out.pr1ntln("and through the woods");

system.out.println("to Grandmother's house we go");

}

}

Answer:

Line 2: Invalid Syntax for the main method. The main method takes the form

public static void main (String [] args) { }

or

public static void main (String args []) { }

Line 3: The syntax to print is wrong.

To print on a new line, make use of System.out.println(".."); not System.out.print1n();

Line 4:

To print on a new line, make use of System.out.println(".."); not System.out.pr1ntln();

Line 5:

The case of "system" is wrong.

The correct case is sentence case, "System.out.println" without the quotes

The correct program goes, this:

public class DebugOne3{

public static void main(String [] args){

System.out.println("Over the river");

System.out.println("and through the woods");

System.out.println("to Grandmother's house we go");

}

}

Explanation:

3 0
3 years ago
What is the purpose of the graphic language?
solmaris [256]

Answer:

enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.

5 0
3 years ago
What was the Strategic Air Command?
Lemur [1.5K]

I'm not sure UBS hand UBS d es. used ins d UBS d jbs is. DHS. u s dibs us dibs de DJ d DJ is end dijjee job DJ dje had d USB e ujjde in dr. hvdn. jdjhe

6 0
3 years ago
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