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gulaghasi [49]
3 years ago
10

Can someone please tell me how to do these problems

Mathematics
1 answer:
kow [346]3 years ago
4 0
These are so easy, you won't believe it !

A negative exponent only means

       "Put all of this in the denominator, and make the exponent positive."

So    (any number)^negative power =

                     1 / (the same number)^(the same power but not negative) .

The first few problems on that sheet:

1).  5^-3  =  1 / 5^3

2).  6^-10  =  1 / 6^10

3).  (-2)^-5  =  1 / (-2)^5

Got it ?    You can do the rest of them now in about 2 minutes. 
You might be interested in
The sum of the measures of angle Y and angle Z is 180 degrees. Angle Y measures (3x + 20) degrees and Angle Z measures x degrees
Minchanka [31]
A)
The question tells us that
y + z = 180
And
y=3x+20
z=x

So we put them in the first formula:

y + z = 180
(3x + 20) + x = 180

Add and get x to one side:
4x + 20 = 180
4x + 20 - 20 = 180-20
4x = 160
Divide both sides by 4
x = 40

B)
Put x back in to equation to get size of each angle:

Y =3x +20
Y=3(40)+20
Y=120+20
Y=140

Z=x
Z=40

Verify: y+z=180
140+40=180
180=180
8 0
2 years ago
Which function is most closely represented by the graph ?
Helen [10]

Answer:

3 + 3/4x

Step-by-step explanation:

it is 3 up and 4 left so y over x for the the slope. mx +b

3 0
3 years ago
Can someone help me?
Ann [662]

Answer:4/3

Step-by-step explanation:

2/6=x/4 cross multiply

6x=8 x=8/6 =4/3 Divide and simplify

7 0
3 years ago
Write 24 over 40 in simplest form
dsp73
Three over five or 3/5
6 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL⎯⎯⎯⎯⎯? Enter your answers in the boxe
algol [13]
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint of segment JK is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

Answer: The coordinates are (-1, -3), (1, -3)
6 0
3 years ago
Read 2 more answers
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