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3 years ago

9

Solve for x.

1 answer:

VashaNatasha [74]3 years ago

3 0

After the distribution of x, you move 6 to the other side of the equation and then divide by three to get x=2. Therefore, the answer is c.

Hope this helps you!

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50 written as a product of its prime fac<br> tors

Maru [420]

Start by identifying any factor of 50 and then rewriting 50 to include that one factor and another:

50 = 5 * 10 5 is prime, but 10 is not. Thus, factor 10:

50 = 5 * 5 * 2 This is 50 as a product of its prime factors 5, 5 and 2.

7 0

3 years ago

Use function notation to write the equation of the line

blondinia [14]

$f(x)=mx+b\to y=mx+b$

We have two points:

$(-3,\ 0);\ (-4,\ 7)$

The point slope form of the line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute

$m=\dfrac{7-0}{-4-(-3)}=\dfrac{7}{-1}=-7$

$y-0=-7(x-(-3))\\\\y=-7(x+3)\\\\y=-7x-21$

Answer:

$f(x)=-7x-21$

8 0

3 years ago

Renaming improper fractions as whole or mixed numbers 17-4

murzikaleks [220]

17/4 as a mixed fraction would be 4 1/4

4 0

3 years ago

HELP ASAP ILL GIVE BRAINLIEST

musickatia [10]

Answer:

y=−2x−10

Step-by-step explanation:

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2 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago