Answer:
Step-by-step explanation:
You would start by writing the expression for “subtract 3 from 15", which would be , then you would add on "then divided by 6", which would make it
I'll do the first two to get you started
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Problem 1
A = 3 = starting value
B = 10 = ending value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (10-3)/3 ] * 100%
C = (7/3) * 100%
C = 2.3333333 * 100%
C = 233.33333%
C = 233.3%
The positive C value means we have a percent increase. If C was negative, then we'd have a percent decrease.
<h3>Answer: 233.3% increase</h3>
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Problem 2
A = 9 = start value
B = 20 = end value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (20-9)/9 ] * 100%
C = (11/9)*100%
C = 1.2222222222*100%
C = 122.22222222%
C = 122.2%
<h3>Answer: 122.2% increase</h3>
Answer:
178 miles
Step-by-step explanation:
Let Eric has driven d miles.
As the rate of charge of driving the truck = 76 cents /mile
So, the charge of driving the truck for d miles = 76d cents= $0.76d
The base fee of the truck was $16.95.
Total money paid at the time of returning the truck = $152.23
So, 16.95+0.76d=152.23
0.76d= 152.23-16.95=135.28
d=135.28/0.76
d=178
Hence, he drives 178 miles.
It is 5 you just have to count
