Using a^2-b^2 = (a-b)(a+b) you can factor the expression:
(3x^3-4y^3)(3x^3+4y^3)
Answer:
<em>a</em><em> </em><em>credito</em><em>r</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>leader</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>entitled</em><em> </em><em>to</em><em> </em><em>rec</em><em>eive</em><em> </em><em>the</em><em> </em><em>pa</em><em>y</em><em>ment</em><em> </em><em>f</em><em>rom</em><em> the</em><em> </em><em>browser</em>
Answer:
6
Step-by-step explanation:
[x-2]=[4.7-2]=[2.7]=2
f(4.7)=3*2=6
Answer:
13r²(2rs + 4r³ - 3s⁴)
Step-by-step explanation:
In equation 26r³s + 52r⁵ - 39r²s⁴;
The GCF of 26, 52, and 39 = 13
The GCF of r³, r⁵ and r² = r²
The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")
Now we can factor out 13r² from all three expressions;
26r³s + 52r⁵ - 39r²s⁴
=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>
To factor it all together;
<u>13r²(2rs + 4r³ - 3s⁴)</u>
Hope this helps!
Answer:
30
Step-by-step explanation:
