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ira [324]
3 years ago
10

Hydraulic press is called an instrument for multiplication of force. Why?

Physics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

Hydraulic press is called an instrument for multiplication of force. Why? Because it uses Pascal's idea and  principle: F=p*S. If we apply small force to small piston you will generate a pressure. According to Pascal's law pressure is the same everywhere in closed system so the same pressure will act on large piston on the other side too.

Explanation:

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Stairway must have uniform riser height and tread depth; variations in riser height or tread depth shall not be over _______ inc
alexandr1967 [171]

Answer:

\frac{3}{8} inches

Explanation:

the variations in riser height or tread depth should not be grater than \frac{3}{8} inches that is equal to 9.5 mm but the maximum riser height should be the  \frac{81}{4} inch  but variation in riser height should not exceed to \frac{3}{8} inches. The minimum riser height should be 7 inches which is equal to the 178 mm

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4 years ago
Current cannot flow through a circuit when the switch is _____.
Akimi4 [234]

Answer:

Open

Closed

Explanation:

An open circuit is an electrical circuit in which the electric current does not circulate because it is interrupted or not communicated by means of an electrical conductor. While in a closed circuit, the current, that is the flow of electrons, travels from the beginning of the circuit to the end.

4 0
3 years ago
Read 2 more answers
Enrico is having trouble telling the difference between the sound of a tuba and the sound of a piccolo. Even though a piccolo pr
Nonamiya [84]

Answer: Pitch

Explanation:

Pitch of sound is defined as the factor that monitors the sound quality through produced vibrations rate.It helps in determination of sounds tone in terms highness or lowness.

According to the question,Enrico is finding difficulty in judging the difference between pitch sound of tuba and piccolo as per their tone in terms of high or low.

4 0
3 years ago
Motion of a light source, like stars in distant galaxies, causes the spectral lines to shift positions as well. An object's moti
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the speed and direction the object is moving.


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3 years ago
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Point charges q1=50μCq1=50μC and q2=−25μCq2=−25μC are placed 1.0 m apart. (a) What is the electric field at a point midway betwe
avanturin [10]

Answer:

a) E = 2.7x10⁶ N/C

b) F = 54 N

Explanation:

a) The electric field can be calculated as follows:

E = \frac{Kq}{d^{2}}

<u>Where</u>:

K: is the Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

d: is the distance

Now, we need to find the electric field due to charge 1:

E_{1} = \frac{9 \cdot 10^{9} N*m^{2}/C^{2}*50 \cdot 10^{-6} C}{(0.5 m)^{2}} = 1.8 \cdot 10^{6} N/C

The electric field due to charge 2 is:

E_{2} = \frac{9 \cdot 10^{9} N*m^{2}/C^{2}*(-25) \cdot 10^{-6} C}{(0.5 m)^{2}} = -9.0 \cdot 10^{5} N/C

The electric field at a point midway between them is given by the sum of E₁ and E₂ (they are in the same direction, that is to say, to the right side):

E_{T} = E_{1} + E_{2} = 1.8 \cdot 10^{6} N/C + 9.0 \cdot 10^{5} N/C = 2.7 \cdot 10^{6} N/C to the right side                                                                                                

Hence, the electric field at a point midway between them is 2.7x10⁶ N/C to the right side.  

b) The force on a charge q₃ situated there is given by:

E_{T} = \frac{F_{T}}{q_{3}} \rightarrow F_{T} = E_{T}*q_{3}

F = 2.7 \cdot 10^{6} N/C*20 \cdot 10^{-6} C = 54 N

Therefore, the force on a charge q₃ situated there is 54 N.  

I hope it helps you!

3 0
3 years ago
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