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3 years ago

Which are most likely to be used during a routine visit to the dentist?

Physics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

The most likely items to be used are;

Ultrasound and X-rays

Explanation:

A routine visit to a dentist consists of two areas of activities, including;

a) Dental examination and check up

b) Oral prophylaxis, and dental cleaning

The dental examination may involve the use of X-rays, which allow the detection of cavities between the teeth

The dental cleaning can be carried out with the use of an ultrasound cleaner, which allow the cleaning of sensitive teeth without hurting the patient

Therefore, the items most likely to be used during a routine dental visit are ultrasound and X-rays

Xelga [282]3 years ago

7 0

Answer:

ultrasound and x-rays

Explanation:

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A heavy anvil is suspended by a 0.75 m long steel wire that has a mass of 12 g. When the wire is plucked, it hums at its fundame

Dima020 [189]

Explanation:

It is given that,

length of steel wire, l = 0.75 m

Mass of the wire, m = 12 g = 0.012 kg

Fundamental frequency, f = 120 Hz

We need to find the mass of the anvil (m'). The fundamental frequency is given by :

$f=\dfrac{v}{2l}$

v is the speed of the mass

Speed is given by :

$v=\sqrt{\dfrac{T}{\mu}}$

$\mu$ is the mass per unit length, $\mu=\dfrac{m}{l}$

$f=\dfrac{1}{2l}\sqrt{\dfrac{T}{\mu}}$

T is the tension in the wire,

$f=\dfrac{1}{2l}\sqrt{\dfrac{Tl}{m}}$

$T=4f^2lm$

$T=4(120)^2\times 0.75\times 0.012$

T = 518.4 N

Tension in the wire, T = m' g

$m'=\dfrac{T}{g}$

$m'=\dfrac{518.4}{9.8}$

m' = 52.89 kg

So, the mass of the anvil is 52.89 kg. Hence, this is the required solution.

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3 years ago

Two football players are attempting to tackle each other. If one football player has a mass of 100 kg and pushes with a force of

Vaselesa [24]

Answer:

is it 20kg. Two opposing forces pushing onto each other

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3 years ago

A bottle rocket takes off with a = 34.5 m/s2. It

sergiy2304 [10]

Answer:3.4 seconds

Explanation:

Initial velocity(u)=0

acceleration=34.5m/s^2

Height(h)=200m

Time =t

h=u x t - (gxt^2)/2

200=0xt+(34.5xt^2)/2

200=34.5t^2/2

Cross multiply

200x2=34.5t^2

400=34.5t^2

Divide both sides by 34.5

400/34.5=34.5t^2/34.5

11.59=t^2

t^2=11.59

Take them square root of both sides

t=√(11.59)

t=3.4 seconds

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3 years ago

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Harlamova29_29 [7]

Answer:

It is due to the large impulse is imparted on the flour.

Explanation:

A ball is moving faster.

When a ball is moving faster strikes to the flour, the change in momentum is large and thus the impulse imparted on the flour is large.

Impulse = change in momentum

So, as the flour experiences large impulse and large momentum so that the flour spreads out.

If the change in momentum is large so the flour spreads out is more.

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3 years ago

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