What is the cube root of 27a12
2 answers:
3a4
that should be your answer
Answer: The correct answer is 3a⁴
Step-by-step explanation:
Let the term be n
n=³√27a¹²
Recall n√x=x1^n
Therefore it can be rewritten as;
n=(27a¹²)⅓
27 rewritten as: 3³
Therefore;
n=(3³a¹²)⅓
Using the rule of exponents, (X^a)^b=X^a*b, eliminate the exponent outside the parenthesis:
n=(3³a¹²)⅓
On= 3³*⅓ a¹²*⅓
n=3⅓ a¹⅔
n=3¹ a⁴
Since a¹ = a
Therefore;
n = 3a⁴
Hope this helps
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Answer:
a-b=10
Step-by-step explanation:
add all the numbers then round
13+ 14+ 22+ 52+ 63+ 77=241
Round to the nearest ten
a =240
first rounding each number to the nearest ten and then add
13+ 14+ 22+ 52+ 63+ 77
10+10+20+50+60+80 =230
b= 230
a-b = 240-230
= 10
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