What is the cube root of 27a12

Mathematics

2 answers:

Mice21 [21]2 years ago

4 0

3a4

that should be your answer

vekshin12 years ago

3 0

Answer: The correct answer is 3a⁴

Step-by-step explanation:

Let the term be n

n=³√27a¹²

Recall n√x=x1^n

Therefore it can be rewritten as;

n=(27a¹²)⅓

27 rewritten as: 3³

Therefore;

n=(3³a¹²)⅓

Using the rule of exponents, (X^a)^b=X^a*b, eliminate the exponent outside the parenthesis:

n=(3³a¹²)⅓

On= 3³*⅓ a¹²*⅓

n=3⅓ a¹⅔

n=3¹ a⁴

Since a¹ = a

Therefore;

n = 3a⁴

Hope this helps

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