The magnetic force acting on a charged particle moving perpendicular to the field is:
= qvB
is the magnetic force, q is the particle charge, v is the particle velocity, and B is the magnetic field strength.
The centripetal force acting on a particle moving in a circular path is:
= mv²/r
is the centripetal force, m is the mass, v is the particle velocity, and r is the radius of the circular path.
If the magnetic force is acting as the centripetal force, set equal to and solve for B:
qvB = mv²/r
B = mv/(qr)
Given values:
m = 1.67×10⁻²⁷kg (proton mass)
v = 7.50×10⁷m/s
q = 1.60×10⁻¹⁹C (proton charge)
r = 0.800m
Plug these values in and solve for B:
B = (1.67×10⁻²⁷)(7.50×10⁷)/(1.60×10⁻¹⁹×0.800)
B = 0.979T
Answer:
b. amplitude
Explanation:
An electromagnetic waveconsists of electrical oscillations and magnetic fields. The frequency of the wave is directly proportional to its energy and its speed and inversely proportional to its wavelength. Therefore, with the only magnitude with which it has no relation is with its amplitude.
they are made up of rock and gas
P = 10^5 - ρ (average)gh
where ρ (average) = average air density between 0 and 5000 m = (1.22+0.74)/2 = 0.98
we know g & h
I get P = 52470 Pa
