Question

What was the speed of a space shuttle that orbited Earth at an altitude of 1482 km?

Answer 1

Answer:

v = 7121.3 m/s

Explanation:

Answer 2

Answer:

v = 7121.3 m/s

Explanation:

As we know that the centripetal force for the space shuttle is due to gravitational force of earth due to which it will rotate in circular path with constant speed

so here we will have

$\frac{mv^2}{r} = \frac{GMm}{r^2}$

here we know that

r = orbital radius = 6370 km + 1482 km

$r = 7.852 \times 10^6 m$

also we know that

$M = 5.97 \times 10^{24} kg$

now we will have

$v^2 = \frac{(6.67 \times 10^{-11})(5.97 \times 10^{24})}{7.852 \times 10^6}$

$v^2 = 5.07 \times 10^7$

$v = 7121.3 m/s$