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11111nata11111 [884]
4 years ago
9

A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial speed of 32 m/s, what is its new speed?

Physics
1 answer:
Nata [24]4 years ago
7 0

B should be the answer

Look at this example to help you

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The force an ideal spring exerts on an object is given by , where measures the displacement of the object from its equilibrium p
Delvig [45]

Answer:

The correct answer is "1.2 J".

Explanation:

Seems that the given question is incomplete. Find the attachment of the complete query.

According to the question,

  • x₁ = -0.20 m
  • x₂ = 0 m
  • k = 60 N/m

Now,

⇒ W=\int_{x_1}^{x_2}F \ dx

⇒      =\int_{x_1}^{x_2}-kx \ dx

⇒      =-k \int_{-0.20}^{0}x \ dx

By putting the values, we get

⇒      =-(60)[\frac{x^2}{2} ]^0_{-0.20}

⇒      =-60[\frac{0}{2}-\frac{0.04}{2}  ]

⇒      =1.2 \ J

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3 years ago
A pile driver drops from a height of 35 meters
MakcuM [25]

It is good so what is what’s they says didn’t. Fiend. Diehard d fish
3 0
4 years ago
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I am totally stuck on number 7 can someone help!!!
Tresset [83]
The Monera kingdom is different from all of the other kingdoms because it contains organisms that are the most primitive or the most basic living things. The organisms that are in the Monera kingdom are usually classified as bacteria.
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3 years ago
After performing some calculations, your calculator gives you the following results. How will you round them before presenting t
umka2103 [35]

Answer:

⇒ 401.6 ± 7.1 ms

⇒ 57.2 ± 1.6 kg

⇒ 8.1 × 107 ± 2.9 × 105 m

⇒ 2.1 ± 8.8 µN

⇒ 294 ± 0.005 cm

Explanation:

As given all equation we do without calculation we will  get here round these calculations which is given below as  

a) 401.6473 ± 7.0912 ms

⇒ 401.6 ± 7.1 ms

b) 57.212 ± 1.612 kg

⇒ 57.2 ± 1.6 kg

c) 8.12754×107 ± 2.847×105 m

⇒ 8.1 × 107 ± 2.9 × 105 m

d) 2.94 ± 8.803 µN

⇒ 2.1 ± 8.8 µN

e) 294 ± 0.00481 cm

⇒ 294 ± 0.005 cm

6 0
3 years ago
a 2.0 kg hoop rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear spe
e-lub [12.9K]

Answer:

72 J

Explanation:

Total kinetic energy will be tge sum of rotational and translational energy.

Rotational kinetic energy is given by 0.5I\omega^{2} where I is moment of inertia which is given by mr^{2} and here m is mass, r is radius. Also, v=\omega r hence making \omega the subject then \omega=\frac {v}{r} where v is the velocity.

Rotational kinetic energy=0.5I\omega^{2}=0.5mr^{2}\times(\frac {v}{r})^{2}= 0.5mv^{2}

This is same as the formula for translational kinetic energy which is given by 0.5mv^{2}

Therefore, total kinetic energy= 0.5mv^{2}+0.5mv^{2}=mv^{2}

Substituting m with 2 kg and v with 6 m/s then total energy will be 2\times 6^{2}=72 J

7 0
3 years ago
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