Question

A parabola has a vertex at (-3,2). Where is the axis of symmetry?

Answer 1

Answer:

The axis of symmetry of the parabola with a vertex at (-3, 2) is at

x = -1/2

Step-by-step explanation:

Given a quadratic function (parabola) of the form:

y = ax² + bx + c

The axis of symmetry of the function is a vertical line that divides the parabola into two congruent halves. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

This is given as x = -b/2a

We are given a parabola with vertex at (-3, 2). The quadratic function corresponding to this is

y = (x -(-3))(x - 2)

= (x + 3)(x - 2)

= x² - 2x + 3x - 6

y = x² + x - 6

Here, a = 1, b = 1, and c = -6

The axis of symmetry is at

x = -b/2a

= -1/2(1)

= -1/2

Answer 2

Answer:

x=-3

Step-by-step explanation:

If a parabola has a vertex at (h,k), the axis of symmetry is at the point, x=h.

That is, the x-coordinate of the vertex of the given parabola is the axis of symmetry.

Therefore, for a parabola with vertex (-3,2), the axis of symmetry is at x=-3