Question

The population of a certain country is approximated by the following equation, where x is the number of years since 1980 and P is the population in millions P=2.748x + 126.199 Determine the year in which the country had or will have the population of 206,123,000 Show your work

Answer 1

Answer:

In 2010 the population become 206,123,000.

Step-by-step explanation:

Consider the provided equation.

$P=2.748x + 126.199$

Where P represents the population in millions.

We need to determine the year in which the country had population of 206,123,000.

As P is in millions so divide 206,123,000 by one million.

$\frac{206,123,000 }{1,000,000}= 206.123$

Substitute P = 206.123 in above equation.

$206.123=2.748x + 126.199$

$79.924=2.748x$

$x=\frac{79.924}{2.748}$

$x=29.08$

30 year from 1980 the population become 206,123,000.

In 2010 the population become 206,123,000.