Find the real-number root.

Mathematics

1 answer:

Artemon [7]3 years ago

5 0

Answer:

No real root

Step-by-step explanation:

imaginary #s

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What is it called when transformation of the plane which reflects each point and then translates it called

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The figures in a plane can be reflected, rotated, translated or dilated to produce new figures or images.

A transformation that moves all points to the same distance and in the same direction. The final figure looks the same, just moved over. It does not flip or gets rotated. It also does not change size.This type of translation is called glide reflection. Its the summation of translation and reflection.

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Please help !! Picture provided !!!

adelina 88 [10]

Method One
Your calculator might be able to do this. Mine does it like this.
6
nCr
2
=
15

Method 2
You could simply set up 6C2

This gives you
$\frac{n!}{(n- r)! r!} = \frac{6!}{(6 - 2)!2!} = \frac{6!}{4! 2!} = \frac{6*5}{2*1} = 15$

Method Three
You only have to do this a couple of times to see how the cancellation works.

$\frac{6!}{4!2!} = \frac{6*5*\st{4*3*2*1}}{4*3*2*1 * 2*1}$
After all the cancellation takes place you have
6*5/2 = 15

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When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

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$2x^{-3}$ or $\frac{2^1x^{-3}}{1} =\frac{2}{x^3}$

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When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

$\frac{x^2}{y}$ (can't combine because they have different bases of y and x)