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valkas [14]
3 years ago
7

PLEASE HELP ASAP!!!! A huge thanks to anyone who can help me with 14 problems. I'll do anything to return the favor. All true an

d false. I will post two more sets of questions. PLEASE do not cheat and answer a random answer or just one question
1. True or False: Bacteria on legumes are able to fix nitrogen from the air.

2. T or F: Mitosis results in new cells with the same number of chromosomes as the parent cell from which they came.

3. Bile breaks down proteins for digestion.

4. A characteristic common to all biomes is the presence of cycles such as the nitrogen cycle.

5. The DNA molecule has a sugar-phosphate backbone.
Physics
1 answer:
snow_lady [41]3 years ago
4 0
Hello, I see you are in a jam. Lemme help.

1.) True
2.) True
3.) True
4.) True
5.) True

LOL these are all true ;)
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How many grams are in 6.53 moles of Mn?
Westkost [7]

Answer:

359 g Mn

General Formulas and Concepts:

  • Dimensional Analysis
  • Reading the Periodic Table of Elements

Explanation:

<u>Step 1: Define</u>

6.53 mol Mn

<u>Step 2: Find conversion</u>

1 mol Mn = 54.94 g Mn

<u>Step 3: Dimensional Analysis</u>

<u />6.53 \hspace{3} mol \hspace{3} Mn(\frac{54.94 \hspace{3} g \hspace{3} Mn}{1 \hspace{3} mol \hspace{3} Mn} ) = 358.758 g Mn

<u>Step 4: Simplify</u>

<em>We are given 3 sig figs.</em>

358.758 g Mn ≈ 359 g Mn

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3 years ago
Which planet is smaller than Earth’s core?
makvit [3.9K]

Answer:

The answer <em><u>is C. Mars</u></em>. Mars and Mercury are both smaller than Earth's core. Hope this helps you :)

7 0
3 years ago
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If you blow harder into a trumpet you will create a sound wave with a greater
ElenaW [278]

Answer is C

Explanation:

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Which substance requires the most heat to melt 1 kg of the substance? A. Copper B. Mercury C. Gold D. Helium
SOVA2 [1]
I would believe it to be C. Gold, but I'm not quite sure
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50 POINTS!!!!!!!!<br><br> In a GUT (Grand Unified Theory), what is "unified"?
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Subatomic particles

Explanation:

Grand unification theory or GUT is a model that tries to describe the universe.

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