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Natasha2012 [34]
3 years ago
5

Two crates, 3kg and 5 kg respectively, are connected with a thin rope.they are pulled up a rough plane which is inclined at 30de

gree to the horizontal.A force F is applied parallel to the plane as shown as in the diagram accelerating the system of crates at 2ms-2 up the slope.the frictional forces acting on 3kg and 5kg crates are 10N and 17N respectively. Draw a fully labeled free body diagram for each crate. calculate the component of the weight of each crate parallel l to the slope.calculate the magnitude of the applied force F and the tension T in the slope.

Physics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

F = 85.24 N

T = 30.84 N

Explanation:

The parameters given are

Mass of crates = m₁ = 3 kg and m₂ = 5 kg

Component of masses acting along the plane = mgsin(θ)

Which gives;

F - (3×9.81×sin(30) + 10 + 5×9.81×sin(30) + 17) = m×a

So that we have;

2 = (F - 66.24)(3 + 5)

F = 16 + 66.24 = 85.24 N

The tension T between the crates = F × m₁/(m₁+m₂) = 85.24 × 3/(3+5) = 30.84 N

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Answer:

\phi = 0.66 rad

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Explanation:

We have here a simple harmonic motion, so the equation of the position in this motion is:  

x(t)=Acos(\omega t+\phi) (1)

A: Amplitude

ω: angular frequency

φ: phase constant

If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:

v(t)=\frac{dx(t)}{dt}=-A\omega sin(\omega t+\phi) (2)

Let's evaluate (1) and (2) in t=0.

x(0)=Acos(\phi) (3)

v(0)=-A\omega sin(\phi) (4)

Dividing 4 by 3 we have:

\frac{v(0)}{x(0)}=-\omega tan(\phi)

\phi = tan^{-1}(\frac{-v(0)}{\omega x(0)})

\phi = 0.66 rad

Now, using (3) we can find the amplitude.

A = \frac{x(0)}{cos(\phi)} = 5.06 cm

I hope it helps!                            

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What is the period of a pendulum that takes 5 seconds to make a complete back and forth vibration
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Explanation:

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-A period is calculated as the time taken for a complete swing divided by one cycle:

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You are fixing a transformer for a toy truck that uses an 8.0-V emf to run it. The primary coil of the transformer is broken; th
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Answer:

a. The primary turns is 60 turns

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Applying the transformer formula which is

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If the primary voltage is V1 240 volts hence the secondary voltage V2 will be (to get the voltage of the secondary coil using emf substitute the values of the previously gotten N1 and N2 using V1 as 240 volts)

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