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Natasha2012 [34]
3 years ago
5

Two crates, 3kg and 5 kg respectively, are connected with a thin rope.they are pulled up a rough plane which is inclined at 30de

gree to the horizontal.A force F is applied parallel to the plane as shown as in the diagram accelerating the system of crates at 2ms-2 up the slope.the frictional forces acting on 3kg and 5kg crates are 10N and 17N respectively. Draw a fully labeled free body diagram for each crate. calculate the component of the weight of each crate parallel l to the slope.calculate the magnitude of the applied force F and the tension T in the slope.

Physics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

F = 85.24 N

T = 30.84 N

Explanation:

The parameters given are

Mass of crates = m₁ = 3 kg and m₂ = 5 kg

Component of masses acting along the plane = mgsin(θ)

Which gives;

F - (3×9.81×sin(30) + 10 + 5×9.81×sin(30) + 17) = m×a

So that we have;

2 = (F - 66.24)(3 + 5)

F = 16 + 66.24 = 85.24 N

The tension T between the crates = F × m₁/(m₁+m₂) = 85.24 × 3/(3+5) = 30.84 N

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lubasha [3.4K]

Answer:

t1 = t2 + 3.02         V = 41.5

V t1 - 1/2 g t1^2 = V t2 - 1/2 g t2^2

Both stones reach the same height after the specified times

V (t1 - t2) = g/2 (t1^2 - t2^2) = g/2 (t1 - t2) (t1 + t2)

2 V / g = t1 + t2 = 2t1 + 3.02

t1 = V / g - 1.51 = 41.5 / 9.8 -1.51 = 2.72 s

t2 = t1 + 3.02 = 5.74 sec

Check:

41.5 * 2.72 - 4.9 * 2.72^2 = 76.6 m

41.5 * 5.74 - 4.9 * 5.74^2 = 76.8 m

Speed of second stone = 41.5 - 9.8 * 2.72 = 14.8 m/s

7 0
2 years ago
An alkane has molecular weight 86. Write its molecular formula. What will be its physical state?
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C6H14

Gaseous state

it's unsaturated hence gaseous

8 0
3 years ago
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A race car has a centripetal acceleration of 13.33 m/s^2 as it goes around a curve. if the curve is a circle with a radius 30 m
anzhelika [568]

Answer:

The speed of the car, v = 19.997 m/s

Explanation:

Given,

The centripetal acceleration of the car, a = 13.33 m/s²

The radius of the curve, r = 30 m

The centripetal force acting on the car is given by the formula

                                   F = mv²/r

Where    v²/r is the acceleration component of the force

                                       a = v²/r

Substituting the values in the above equation

                                        13.33 = v²/30

                                         v² = 13.33 x 30

                                         v² = 399.9

                                         v = 19.997 m/s

Hence, the speed of the car, v = 19.997 m/s

3 0
2 years ago
Select the correct answer.
kipiarov [429]

Answer:

A

Explanation:

If the object is moving at a constant speed, the object isn't accelerating as the velocity doesn't change.

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3 years ago
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