Answer: The x-component of the total force 97N
Explanation:
Given the following :
Mass (M) of skier = 73.9 kg
Pull force on the skier = 105N
Angle of pull = 22.5°
The direct backward force directly pulling the skier = 74.8N
the x-component of the total force on the skier
The horizontal component of the force = Magnitude of the pulling force × cosine of the angle of pull (FCosΘ)
FCosΘ = 105cos22.5°
105cos22.5 = 105 × 0.9238795
= 97.007350
= 97N
The backward force acting directly backward = 74.8N
Therefore, net x - component of the total force equals ;
97N - 74.8N = 22.2N
