Let 3<em>n</em> + 1 denote the "number" in question. The claim is that
(3<em>n</em> + 1)² = 3<em>m</em> + 1
for some integer <em>m</em>.
Now,
(3<em>n</em> + 1)² = (3<em>n</em>)² + 2 (3<em>n</em>) + 1²
… = 9<em>n</em>² + 6<em>n</em> + 1
… = 3<em>n</em> (3<em>n</em> + 2) + 1
… = 3<em>m</em> + 1
where we take <em>m</em> = <em>n</em> (3<em>n</em> + 2).
I think the answer its 1.8 percent because if you subtract 15-13.2 comes out to be 1.8.
but l also think it could be 12 percent error.
Two hours and thirty minutes if that's the question
Answer:
2.9403x10^15
Step-by-step explanation:
plsss mark as brainliestt :)
10% as a decimal (a value between 0 and 1) is 0.1