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4 years ago

6

What is volume to a cube?

2 answers:

Sergio039 [100]4 years ago

5 0

Answer: The volume of a cube is 6s^3

Step-by-step explanation:

Since a cube is equivalent on all sides, and a cube has 6 sides, you multiply the length of one side (s) by the number of sides (6)

For example, let’s say the length is 7.2”

You would multiply 6 and 7.2^3” to get 2239.49 cubic inches

Hope this helps!

Setler79 [48]4 years ago

4 0

Volume = length x width x height. You only need to know one side to figure out the volume of a cube. The units of measure for volume are cubic units. Volume is in three-dimensions. You can multiply the sides in any order.

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Solve for y<br> 4.2x - 1.4y = 2.1

Harlamova29_29 [7]

4.2x - 1.4y = 2.1 |multiply both sides by 10

42x - 14y = 21 |subtract 42x from both sides

-14y = 21 - 42x |change signs

14y = 42x - 21 |divide both sides by 14

y = 3x - 1.5

8 0

3 years ago

Calculate the average velocity of a dancer who moves 5 m toward the left of the stage over the course of 15 s. ** Velocity = dis

Aloiza [94]

Answer:

V = Displacement / Time

V = 5 m / 15 s

V = 1/3 m/s

-hope this helped

8 0

3 years ago

Read 2 more answers

NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

Find the area of the new figure.<br>

AleksandrR [38]

The side is 3 so it would be 3 times 5, your answer is 15

5 0

2 years ago

$175 at 5.45% for 36 months

sweet-ann [11.9K]

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

$175 at 5.45% for 36 months

<u>First, we need to determine the monthly interest:</u>

Monthly interest= 0.0545/12= 0.004542

<u>Now, we will calculate the interest earned using both simple and compound interest:</u>

Simple interest:

I= P*r*t

I= 175*0.004542*36

I= $28.61

Compound interest:

I= PV*(1+i)^n - PV

I= 175*(1.004542^36) - 175

I= $31.01

3 0

3 years ago