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ki77a [65]
3 years ago
13

Find the current through a person and identify the likely effect on her if she touches a 120 V AC source in the following circum

stances. (Note that currents above 10 mA lead to involuntarily muscle contraction.)
(a) Find the current if she is standing on a rubber mat and offers a total resistance of 350 kΩ.
Physics
1 answer:
Pie3 years ago
4 0

Answer:the current is 0.34A

Explanation: she will not experience any electrical injuries since she is standing on a mat, hence she is properly earthed.

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Which process is an example of a physical change?
Anit [1.1K]

Answer:

Option A

Carrots are cut into small pieces and mixed into a salad

Explanation:

When physical changes occur, the actual composition remain the same but the molecules are re-arranged. Therefore, when carrots are cut into smaller pieces and mixed into salad, there will be no chemical reaction hence the actual composition will remain the same despite being cut and molecules in it re-arranged. Considering the other options, new substances are formed hence they are deemed as chemical changes. Therefore, option A is correct.

8 0
3 years ago
A Martian rover found an interesting rock that could contain signs of what Mars was like long ago. It grabbed
kodGreya [7K]

Answer:

It would be PE=16kg * 9.8 m/s^2 * 1m = 160 J

Explanation:

The person who asked this question ended up answering his own question so I'm here to let you know all that the answer was founded by the person whos posted the question himself full credit goes to him :)

3 0
3 years ago
A DC generator is the same as a(n)
nikdorinn [45]

Answer:

A DC generator is the same as a(n)

C. armature

7 0
3 years ago
Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 2.6 m long, its mass is 0.5
Irina-Kira [14]

Answer:

15.13 m/s

Explanation:

The wave speed of the stretched rope can be calculated using the following formula

v = \sqrt{\frac{F_T}{\mu}}

where F_T = 44N is the tension on the rope and \mu = m/L = 0.5 / 2.6 = 0.1923 kg/m is the density of the rope per unit length

v = \sqrt{\frac{44}{0.1923}} = \sqrt{228.8} = 15.13 m/s

6 0
3 years ago
How many questions are on cumulative tests? on edgenutiy
Evgesh-ka [11]
Roughly 50 for me i dont know about anyone else
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