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3 years ago

Select an equation for this graph please help me.

Mathematics

1 answer:

MrRissso [65]3 years ago

3 0

A is the answer.

First, figure out all the coordinates for the points marked red( I Did this for all except first one, which was not on the right point)

They were:

-1,1

0,2

1,4

2,8

3,16.

Then, we must do trial and error for each of the options until we find one that fits perfectly. Luckily, the first option was right!

Hope this helps

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Can someone please explain

ankoles [38]

Start by defining variables (things you don't know). Let's make:
t = number of true/false questions
m = number of multiple choice questions

Equation #1
total questions on the test (given to be 20) is then:
t + m = 20

Equation #2
Multiply the number of questions by the points it's worth to get the total points
3t + 11m = 100

Now, you can use substitution to combine the two equations.

t + m = 20
by subtracting m from both sides, equation 1# becomes..
t = 20 - m

substitute t for 20 - m in the second equation.
3(20 - m) + 11m = 100

Solve for m.
3(20 - m) + 11m = 100
60 - 3m + 11m = 100
8m = 100 - 60
8m = 40
m = 5

There are 5 multiple choice questions on the test.
Now use this to find t.
t + m = 20
t + 5 = 20
t = 20 - 5
t = 15

there are 15 true/false questions on the test.

7 0

3 years ago

How do you solve x squared +2x-15= 0

Veseljchak [2.6K]

+2x-15=0
+2x=0+15
2x=15
X=15/2
X=15/2 or 7,5

5 0

3 years ago

PLEASE HELP WITH THE FOLLOWING. WILL GIVE BRAINLIEST. THANK YOU

Marina86 [1]

Answer:

Step-by-step explanation:

First, we need to use the Pythagorean Theorem to find the third side. We will then use the law of cosines to find the angle.

2√15² = 2√6² + b²

60 = 24 + b²

Subtract 24

36 = b²

b = 6

Now, that we have all three sides, we will use the law of cosines to figure out the angle.

c² = a² + b² - 2abCosC°

Substitute the values in.

6² = 2√15² + 2√6² - 2(2√15)(2√6)CosC°

36 = 60 + 24 - 2(37.947331922)CosC°

36 = 60 + 24 - 75.894663844CosC°

36 = 84 - 75.894663844CosC°

Subtract 84

-48 = -75.9CosC°

0.63241106719 = CosC°

Arccos (0.63241106719) = 50.77176844°

The largest acute angle is approximately 50.8°

4 0

3 years ago

A hunter is at a point on a riverbank. He wants to get to his cabin located 2 Miles North and 8 Miles West. He can travel 5 Mph

miskamm [114]

Answer:

Option A

Step-by-step explanation:

A hunter travels to his cabinet located at 2 Miles North and 8 Miles West.

Let "d" be the distance traveled before reaching the rocky ground at point say "P". Let the cabin be at "C"

The distance between C and P is given by

$\sqrt{(2^2+(8-d)^2}\\$

Let "t" be the time taken to travel distance CP.

$T = \frac{d}{5} + \frac{\sqrt{2^2+(8-d)^2} }{3}$

Minimum time will be when "t" is equal to zero

Differentiating the above equation wrt "d", we get -

$= \frac{1}{5} + \frac{1}{3} (\frac{-2(8-d)}{2\sqrt{2^2+(8-d)^2} } )= 0\\\frac{1}{5} = \frac{1}{3} \frac{(8-d)}{\sqrt{4+(8-d)^2} } \\3\sqrt{4+64+d^2-16d} = 40-5d\\$

On squaring both the sides , we get -

$3\sqrt{4+64+d^2-16d} = 40-5d\\9(68+d^2-16d)= 1600+25d^2 -400d\\612+9d^2-144d=1600+25d^2 -400d\\16d^2-256d+988=0\\d_1 = 9.5\\d_2 = 6.5$

"d" cannot be greater than 8 miles.

Hence, the value of "d" is equal to $6.5$

Option A

8 0

3 years ago

Plz help with these ill post more with more points

zaharov [31]

Answer:

I think it is D I'm not sure

Step-by-step explanation:

If two angle and one ️ are congruent to two angles of a second ️ and also if the included sides are congruent, then the ️ are congruent. If in ️ PRQ and TUV, angle P=angle T, angle R=angle and PR=TU, then triangles PRQ is congruent to triangle TUV

5 0

3 years ago