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mamaluj [8]
3 years ago
9

ASAP! What is the total number of electrons that can occupy the f sublevel? a 2 electrons b 6 electrons c 10 electrons d 14 elec

trons
Chemistry
2 answers:
vaieri [72.5K]3 years ago
4 0

Answer:

14 electrons

Explanation:

The total number of electrons that can occupy the f sublevel is 14.

The d sublevel can have 10 electrons.

The p sublevel can have 6 electrons

The s sublevel can have 2 electrons.

Makovka662 [10]3 years ago
3 0

Answer:

D) 14 Electrons

Explanation:

I took the test and got it right

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Arisa [49]
It is 95% ethanol and 5%water
I’m pretty sure hope you get it right!
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8 0
3 years ago
How many hydrogen atoms are in 7.80 mol of ammonium sulfide?
Alexus [3.1K]

The number  of hydrogen atoms that are in 7.80 moles of ammonium sulfide are  3.756 x 10^25  atoms


<u>calculation</u>

Step  1:  calculate  the  moles of H  in  (NH4)2S

 since there are 8 atoms of  H in (NH4)2S  the moles of

   H =  8 x7.80 =  62.4  mole

 Step  2: use of Avogadro's law  constant  to  determine the number  of  H atom

          that is 1 mole = 6.02 x10^23 atoms

                     62.4 moles=?  atoms

  • cross  multiplication

= [ 62.4  x 6.02 x10^23]/  1 mole= 3.756  x10^25    atoms

7 0
3 years ago
Read 2 more answers
Speed.
Alexus [3.1K]
Increases with

hope this helped :))
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5 0
3 years ago
How many molecules of sodium chloride are in 2.5 moles??
sergiy2304 [10]

Answer:

1.5x1024

Explanation:

7 0
3 years ago
In the laboratory you dissolve 13.9 g of potassium phosphatein a volumetric flask and add water to a total volume of 250mL.
tensa zangetsu [6.8K]

Answer:

Molarity of the solution? 0,262 M.

Concentration of the potassium cation? 0,786 M.

Concentration of the phosphate anion? 0,262 M.

Explanation:

Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:

K₃PO₄ → 3 K⁺ + PO₄³⁻ <em>(1)</em>

Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.

There are 250 mL of solution≡0,25 L

The moles of K₃PO₄ are:

13,9 g of K₃PO₄ ×\frac{1mol}{212,27 g} = 0,0655 moles of K₃PO₄

The molarity of the solution is:

\frac{0,0655 moles}{0,25L} = 0,262 M

In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:

0,0655 moles×3 = 0,1965 moles

The concentration is:

\frac{0,1965 moles}{0,25L} = 0,786 M

The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M

I hope it helps!

4 0
3 years ago
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