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3 years ago

An isopropyl solution contains 70 ml of isopropyl alcohol in 1.8 L of water. What is the percent by volume of the alcohol

Chemistry

1 answer:

xenn [34]3 years ago

5 0

Answer:

3.74%

Explanation:

We express a solution's volume by volume percent concentration, % v/v,

Take the ratio of the isopropyl alcohol (IPA) volume to the total volume of the solution, which is 1800 mL of water+ 70 mL of IPA,

and multiply by 100 to get the percentage: 70/(1800+70) *100 = 0.0374*100 = 3.74%

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A material has a density of 8.9 g/cm^3. You have 3 grams of the substance. How much space does it take up? a. 0.3cm3 b. 3.0 cm3

My name is Ann [436]

D = m/ V

8.9 = 3 / V

V = 3 / 8.9

V = 0.3 cm³

Answer A

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What is used to classify galaxies?star typesestimated agecolorshape

lianna [129]

The correct answer among the choices given is the last option. Galaxies are classified according to their shapes or visual morphology. There three main types of galaxies currently. They are the elliptical, spiral and irregular. Elliptical galaxies are like a spheriod or an elongated sphere. Spiral galaxies are characterized and distinguished by having a bulge, a disk and a halo. Lastly, irregular galaxies do not have regular or symmetrical shape.

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3 years ago

Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl

tensa zangetsu [6.8K]

Answer:

$[SO_2Cl_2] = 0.09983 M$

Explanation:

Write the balance chemical equation ,

$SO_2Cl_2((g) = SO_2(g) + Cl_2(g)$

initial concenration of $SO_2Cl_2((g) =0.1M$

lets assume that degree of dissociation= $\alpha$

concenration of each component at equilibrium:

$[SO_2Cl_2] = 0.1-0.1\alpha$

$[SO_2] = 0.1\alpha$

$[Cl_2] = 0.1\alpha$

$Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}$

$Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}$

as $\alpha$ is very small then we can neglect $1-\alpha$

therefore ,

$Kc ={0.1\alpha \times \alpha}$

$\alpha =\sqrt{\frac{Kc}{0.1}}$

$\alpha = 1.73 \times 10^{-3}$

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$[SO_2Cl_2] = 0.09983 M$

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3 years ago

part of the SO2 that is introduced into the atmosphere by combustion of sulfur containing compounds ends up being converted to s

alisha [4.7K]

Answer:

5 mol.

Explanation:

Equation of the reaction

2SO2 + 2H2O + O2 --> 2H2SO4

By stoichiometry, 2 moles of SO2 reacted with 2 moles of water and 1 mole of O2 to give 2 mole of sulphuric acid.

Number of moles:

5.0 mol SO2

4.0 mol O2

20.0 mol H2O

Calculating the limiting reagent,

5 mol of SO2 * 1 mol of O2/2 mol of SO2

= 2.5 mol of O2(4 mol of O2 is present)

5 mol of SO2 * 2 mol of H2O/2 mol of SO2

= 5 mol of H2O(20 mol of H2O)

SO2 is the limiting reagent.

Therefore, number of moles of H2SO4 = 5 mol of SO2 * 2 mol of H2SO4/2 mol of SO2

= 5 mol of H2SO4.

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3 years ago

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Anestetic [448]

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