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3 years ago

An isopropyl solution contains 70 ml of isopropyl alcohol in 1.8 L of water. What is the percent by volume of the alcohol

Chemistry

1 answer:

xenn [34]3 years ago

5 0

Answer:

3.74%

Explanation:

We express a solution's volume by volume percent concentration, % v/v,

Take the ratio of the isopropyl alcohol (IPA) volume to the total volume of the solution, which is 1800 mL of water+ 70 mL of IPA,

and multiply by 100 to get the percentage: 70/(1800+70) *100 = 0.0374*100 = 3.74%

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OlgaM077 [116]

Answer:

32.711

Explanation:

1 yard = 0.0009144 km

1 week = 168 hrs

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3 years ago

2 Zn + O2 → 2 ZnO

meriva

Answer:

we need 6.0 moles of zinc (Zn)

Explanation:

Step 1: Data given

Number of moles ZnO produced = 6.0 moles

Step 2: The balanced equation

2 Zn + O2 → 2 ZnO

For 2 moles Zinc we need 1 mol Oxygen to produce 2 moles Zinc oxide

Step 3: Calculate moles zinc

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3 years ago

Question 13 (1 point)

crimeas [40]

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3 years ago

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gulaghasi [49]

Answer:

A directory of relatives' phone numbers

Hope this helps

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2 years ago

How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol

SVEN [57.7K]

<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u /> $3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} )$ = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

3 0

2 years ago