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Lady_Fox [76]
3 years ago
11

Mikayla says that air is an element since it has oxygen in it. Jose says that air is a mixture because each part of air keeps it

s properties. Grant says that both Mikayla and Jose are wrong, because air is a compound. Who is correct and why? Group of answer choices
Chemistry
1 answer:
tatyana61 [14]3 years ago
5 0

Answer: Jose is correct because air is a mixture of gases ( both elements and compounds).

Explanation:

An element consist of only one type of atom and a compound made up of 2 or more types of elements joined together ( by ionic or covalent bonds).

Whereas air around us is a mixture of gases (both elements and compounds) like nitrogen, oxygen, argon, and carbon dioxide, and very small amounts of other gases and water vapors

Hence, Jose is correct because air is a mixture of gases ( both elements and compounds).

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What fraction of the earth did the former continental glaciers cover?
bija089 [108]
<span>i think one third part of the earth </span>
5 0
3 years ago
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A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask "S" to a 25.00 mL volumetric flask "B," which is then di
Leto [7]

Answer: the molarity of the solution in volumetric flask "B' is 0.0100 M

Explanation:

Given that;

the Molarity of stock solution M₁ = 1.25M

The molarity os solution in volumetric flask A (M₂) = M₂

Volume of stock solution pipet out (V₁) = 5.00mL

Volume of solution in volumetric flask A V₂ = 25.00mL

using the dilution formula

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

WE SUBSTITUTE

M₂ =  ( 1.25 × 5.00 ) / 25.00 mL

M₂ = 0.25 M

Now volume of solution pipet out from volumetric flask A V₂ = 2.00 mL

Molarity of solution in volumetric flask B (M₃) = M₃

Volume of solution in volumetric flask B V₃ = 50.00m L

Using dilution formula again

M₂V₂ = M₃V₃

M₃ = M₂V₂ / V₃

WE SUBSTITUTE

M₃ = ( 0.25 × 2.0) / 50.0

M₃ = 0.0100 M

Therefore the molarity of the solution in volumetric flask "B' is 0.0100 M

5 0
3 years ago
Help me please!! :D​
dem82 [27]

Answer: Solar eclipse

Explanation:

4 0
3 years ago
A chemist heats the block of copper as shown in the interactive, then places the metal sample in a cup of oil at 25.00 °C instea
Mazyrski [523]

When the oil is added to the heated copper, the energy in the system is

conserved.

  • The mass of the oil in the cup, is approximately <u>64.73 grams</u>.

Reasons:

The question parameters are;

Temperature of the oil in the cup = 25.00°C

Final temperature of the oil and copper, T₂ = 27.33 °C

Specific heat of copper, c₂ = 0.387 J/(g·°C)

Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)

Required:

The<em> mass of oil</em> in the cup.

Solution:

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating, T₂ = 65.17°C

Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C

Heat lost by copper = Heat gained by the oil

  • m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)

Therefore, we get;

17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)

262.4219136 = 4.0542·m₁

m₁ ≈ 64.73

  • The mass of the oil in the cup, m₁ ≈ <u>64.73 g</u>

Learn more here:

brainly.com/question/21406849

<em>Possible part of the question obtained from a similar question online, are;</em>

<em>The mass of the copper, m₂ = 17.920 g</em>

<em>Temperature of copper after heating = 65.17°C</em>

6 0
3 years ago
A hydrate of CuSO4 has a mass of 12.98 g before heating. After heating, the mass of the anhydrous compound is found to be 9.70 g
lukranit [14]
Explanation of the strategy: 1) calculate the mass of water and convert to number of moles, 2) convert the mass of anhydrous CuSO4 to moles, and, 3)calculate the mole ratio of water to CuSO4 anhydrous

1) Calculate the mass of water:

mass of water = mass of the hydrate CuSO4 - mass of the anhydrous compound

mass of water = 12.98 g - 9.70 g = 3.28g

2) Calculate the number of moles of water

number of moles = mass in grams / molar mass

molar mass of water = 18.01 g/mol

number of moles of water = 3.28 g / 18.01 g/mol = 0.182 mol

3) Calculate the number of moles of CuSO4 anhydrous

number of moles = mass in grams / molar mass

molar mass of Cu SO4 = 159.6 g/mol

number of moles of CuSO4 = 9.70g / 159.6 g/mol = 0.0608 moles

4) Calculate the ratio moles of water / moles of CuSO4

ratio = moles of water / moles of CuSO4 = 0.182 / 0.0608 = 2.99 ≈ 3

Therefore the molecular formula is CuSO4 . 3H2O

Name: copper(II) sulfate trihydrate.
4 0
3 years ago
Read 2 more answers
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