Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant =
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r =
M =
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.
The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s
<u>Given data :</u>
Distance of star from earth = 4.3 light years
Observers time = 3.7 years
<h3>Determine the constant velocity the spacecraft must travel </h3>Observers time = 3.7 * 365 * 24 * 60 * 60
Distance of star from earth = 4.3 * 9.46 * 10¹⁵
The velocity the spacecraft must travel will be calculated using the equation
V = distance / time
= ( 4.3 * 9.46 * 10¹⁵ ) / ( 3.7 * 365 * 24 * 60 * 60 )
= 3.49 * 10⁸ m/s
Hence we can conclude that The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s
Learn more about space travelling : brainly.com/question/1344685
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