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trapecia [35]
3 years ago
5

What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.

Physics
2 answers:
Marizza181 [45]3 years ago
6 0

Answer: A.

Explanation:

V = M (kg*m/sec) /m (kg) = 4000/115 = 800/23 = 34.7826.. m/sec

julia-pushkina [17]3 years ago
4 0
<h2>Answer: 34.78 m/s</h2>

Explanation:

The momentum p is given by the following equation:

p=m.V   (1)

Where:

m is the mass of the object

V is the velocity of the object

Finding the velocity from (1):

V=\frac{p}{m}   (2)

V=\frac{4000kg.m/s}{115kg}  

<u>Finally:</u>

V=34.78m/s >>>This is the velocity of the object

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Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c
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Answer:

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Explanation:

following Coulomb's law , the force exerted by 2 point charges between themselves is:

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since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have

r₁₃+r₂₃=d=r₁₂

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r₁₃*(1+√(q₂/q₁))=d

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replacing values

r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m

thus the distance from charge A to C is r₁₃= 1.216 m

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