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3 years ago

What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.

Physics

2 answers:

Marizza181 [45]3 years ago

6 0

Answer: A.

Explanation:

V = M (kg*m/sec) /m (kg) = 4000/115 = 800/23 = 34.7826.. m/sec

julia-pushkina [17]3 years ago

4 0

<h2>Answer: 34.78 m/s</h2>

Explanation:

The momentum $p$ is given by the following equation:

$p=m.V$ (1)

Where:

$m$ is the mass of the object

$V$ is the velocity of the object

Finding the velocity from (1):

$V=\frac{p}{m}$ (2)

$V=\frac{4000kg.m/s}{115kg}$

<u>Finally:</u>

$V=34.78m/s$ >>>This is the velocity of the object

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At 15°C air is transmitted <br>at 340 m/s. Express this speed<br>in Kilometers per hour.

EleoNora [17]

Answer:

1224km/hr

Explanation:

To convert from m/s to km/hr

1000m = 1km

Divide both sides by 1000

1m = 1/1000 km................. (1)

60×60 seconds = 1 hr

3600s = 1hr

Divide both sides by 3600

1s = 1/3600 .............(2)

Divide (2) by (1)

1m/s = 1/1000 ÷ 1/3600 km/hr

1m/s = 1/1000 × 3600/1 km/hr

1m/s = 3600/1000 km/hr

1m/s = 3.6 km/hr .............(3)

To convert 340m/s to km/hr

Multiply (3) by 340

1× 340m/s = 3.6 × 340 km/hr

340m/s = 1224km/hr

I hope this was helpful, please mark as brainliest

7 0

3 years ago

Read 2 more answers

A train at a constant 60.0 km/h moves east for 40.0 min, then in a direction 50.0 degrees east of due north for 20.0 min, and th

son4ous [18]

Answer:

Part a)

$v = 7.57 km/h$

Part b)

$\theta = 67.5 degree$ North of East

Explanation:

Speed of train towards East = 60 km/h

displacement towards East is given as

$d_1 = 40 km$

now it turns towards 50 degree East of North

so its distance is given as

$d_2 = 20 km(sin50 \hat i + cos50\hat j)$

$d_2 = 15.3 \hat i + 12.8 \hat j$

then finally it moves towards west for 50 min

$d_3 = -50 \hat i$

Now the total displacement of the train is given as

$d = d_1 + d_2 + d_3$

$d = (40 + 15.3 - 50)\hat i + 12.8 \hat j$

$d = 5.3\hat i + 12.8 \hat j$

now total time duration of the motion is given as

$T = 40 min + 20 min + 50 min$

$T = 1.83 h$

now average velocity is given as

$v_{avg} = \frac{5.3\hat i + 12.8\hat j}{1.83}$

$v_{avg} = 2.89\hat i + 6.99\hat j$

Part a)

magnitude of the average velocity is given as

$v = \sqrt{v_x^2 + v_y^2}$

$v = \sqrt{2.89^2 + 6.99^2}$

$v = 7.57 km/h$

Part b)

Direction of the velocity is given as

$tan\theta = \frac{v_y}{v_x}$

$tan\theta = \frac{6.99}{2.89}$

$\theta = 67.5 degree$ North of East

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4 years ago

What causes the earths plates to move

Norma-Jean [14]

The intense heat in the earth's core that causes molten rock in the mantle layer to move.

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3 years ago

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A 2.2 kg model rocket is shot straight up in the air from the ground, with an initial velocity of 36.4 m/s. The rocket reaches i

alexandr1967 [171]

Answer:

Explanation:

Ignoring friction, the initial kinetic energy will convert to maximum potential energy at its highest point.

PE = KE

mgh = ½mv²

h = v²/2g

h = 36.4²/ (2(9.81))

h = 67.53109...

h = 67.53 m

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2 years ago

Which of the following describes the normal shape of a DNA molecule?

Rudiy27

Answer:

A. Two strands of nucleotides bonded together at their bases,

twisting to form a double helix

Explanation:

Hope this helps! Can I have brainliest?

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3 years ago