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Sonja [21]
3 years ago
6

________ is a change in the position of a body with respect to time relative to a reference point.

Physics
2 answers:
Scilla [17]3 years ago
8 0

Answer:

Velocity

Explanation:

Velocity is a vector quantity which is defined as the rate of displacement. Displacement is also a vector quantity which is measured as the shortest distance between the final point form the reference point.

Velocity is negative when the displacement is negative, displacement can be negative if taken in opposite direction form the desired direction with respect to the initial point.

zalisa [80]3 years ago
6 0

Answer:

Motion

Explanation:

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Answer:

B.6

Explanation:

speed = distance / time

= 75m / 12s

= 6.25 m/s

The closest answer is b. 6 m/s

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12 N to the right (based on your POV)
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If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the
kodGreya [7K]

Answer:

a)

v = 4.048 *10^6 m/s

b)  

Angular frequency =  1.92 * 10^7

Explanation:

As we know

v =  \frac{qBr}{m}

q is the charge on the electron = 3.2 * 10^{-19} C

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r is the radius of the circle = 0.21 m

mass of the electrons = 6.64 * 10^{-27} Kg

a)

Substituting the given values in above equation, we get -

v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6m/s

b)  

Angular frequency =

\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7

8 0
3 years ago
Find an expression for the kinetic energy of the car at the top of the loop.Express the kinetic energy in terms of m, g, h, and
lyudmila [28]

Answer:

K.E₂ = mg(h - 2R)

Explanation:

The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:

K.E₁ + P.E₁ = K.E₂ + P.E₂

where,

K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)

P.E₁ = Initial Potential Energy = mgh

K.E₂ = Final Kinetic Energy at the top of the loop = ?

P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)

Therefore,

0 + mgh = K.E₂ + mg(2R)

<u>K.E₂ = mg(h - 2R)</u>

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3 years ago
Which system works with the respiratory system for the exchange of gases to take place?
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