Question

Two charges, one with a charge of +10.0 x 10-6 C, the other with a charge of -3 x 10-6 C exert a force on each other with a magnitude of 1.7 Newtons on each other. Is this a repulsive or attractive force. What is the separation distance of these charges?

Answer 1

Answer:

b.

Explanation:

Answer 2

Answer:

Attractive force and r = 0.399 m

Explanation:

One charge is positive and the other charge is negative. Opposite charges attract, so there has to be a force that attracts between them.

q1 = 10.0 x 10^-6 C

q2 = -3 x 10^-6 C

F = 1.7 N

Plug those values into Coulomb's Law:

$F = k\frac{q1q2}{r^{2} } \\1.7 = \frac{(9x10^{9})(10.0 x 10^{-6})(-3 x 10^{-6})}{r^{2} }$

Solve for r

r = 0.399 m