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wlad13 [49]
4 years ago
6

What will happen if an stop able item was to hit an unbreakable item

Physics
1 answer:
nataly862011 [7]4 years ago
7 0
It would either break or stop depends on the density
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Caculate the total charge transferred through a wire carrying a current of 0.5 Ameter for a period of 20 seconds.
Marina CMI [18]

charge = current x time = 0.5x 20=10Coulombs

5 0
3 years ago
Why is force not on a scalar quantity??
snow_lady [41]
Because force always has a direction, it always works towards or against something.


you might know that force,
is rate of change of momentum i.e

force = m (v-u)/t
= (mv - mu )/ t


as we know momentum is a vector quantity so, the rate of change of momentum i.e Force would also be a vector quantity.




momentum = mass × velocity

velocity has a direction so,
momentum has also got a direction.
so, momentum is also a vector quantity.
3 0
3 years ago
Read 2 more answers
To make sure you understand how to use the equation, suppose that there are 1000 habitable planets in our galaxy, that 1 in 10 h
krok68 [10]

Answer:

5

Explanation:

Number of habitable planets = 1000

Fraction of planet with life = 1/10

Fraction of planet with life and civilization (before) = 1/4

Fraction of planet with life and civilization (now) =1/5

Therefore multiplying we have:

1000×1/10×1/4×1/5 = 5

5 0
3 years ago
A rocket fires its engines to launch straight up from rest
alexira [117]
Weow that’s cool but what is your question
3 0
3 years ago
A flat sheet of ice has a thickness of 2.20 cm. It is on top of a flat sheet of crystalline quartz that has a thickness of 1.50
kolezko [41]

Answer:

Distance_{vaccum}=5.19cm

Explanation:

The speed of light in these mediums shall be lower than that in vacuum thus the total time light needs to cross both the media are calculated as under

Total time = Time taken through ice + Time taken through quartz

Time taken through ice = Thickness of ice / (speed of light in ice)

T_{ice}=\frac{2.20\times 10^{-2} \times \mu _{ice}}{V_{vaccum}}

T_{quartz}=\frac{1.50\times 10^{-2} \times \mu _{quartz}}{V_{vaccum}}

Thus in the same time the it would had covered a distance of

Distance_{vaccum}=Totaltime\times V_{vaccum}\\\\Distance_{vaccum}=10^{-2}[2.20\mu _{ice+1.50\mu _{quartz}}]

we have

\mu _{ice}=1.309\\\\\mu _{quartz}=1.542

Applying values we have

Distance_{vaccum}=10^{-2}[2.20\times 1.309+1.50\times 1.542]

Distance_{vaccum}=5.19cm

6 0
4 years ago
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