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fredd [130]
4 years ago
11

Earth is the only planet known to have _____.

Physics
2 answers:
QveST [7]4 years ago
6 0

Answer:

A biosphere

Explanation:

Biosphere refers to the zone of life on a planet. It includes all living elements of a planet. It is also known as Eco-sphere and includes the interaction of all living being with their surrounding.

Of all the planets and exo-planets, Earth is the planet known to have life and thus biosphere.

Whereas atmosphere, lithosphere and cryosphere can be found on other planets as well.

Atmosphere: Layer of air and gases surrounding a planet or any celestial object. (Except Mercury, all the planets of solar system have atmosphere)

Lithosphere: it refers to the rigid outer part of the planet which includes crust and mantle. (All the rocky planets have lithosphere)

Cryosphere: portion of the planets where water is in ice form. (Many exoplanets have been discovered having cryosphere)

postnew [5]4 years ago
4 0

the answer is bioshere

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If a car is traveling at an average speed of 60 kilometers per hour, how long does it take to travel 12 kilometers?
Otrada [13]

Answer: 0.2 hour

Explanation:

Speed = Distance / Time

Time = Distance / Speed

= 12/60

= 0.2 hour

8 0
3 years ago
An empty 2,500 kg train car is headed northbound at a velocity of 5 m/s. Ahead of the first car, an empty 1,500 kg car is headed
Tema [17]

Let the mass of 2500 kg car be m_1 and it's velocity be v_1 and the mass of 1500 kg car be m_2 and it's velocity be v_2 .

After the bumping the mass be M and it's velocity be V.

     By law of conservation of momentum we have

                   m_1v_1+m_2v_2 = MV

                    2500 * 5 + 1500 * 1=4000 * V

                    V = 14000/4000 = 7/2 = 3.5 m/s

So the velocity of the two-car train = 3.5 m/s

9 0
3 years ago
Some expressways are curved, banked and designed to maximize ___________ at higher speeds.
Liono4ka [1.6K]

Answer:

Safety

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6 0
3 years ago
What is a rubens tube
Free_Kalibri [48]

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6 0
3 years ago
Two balls of clay, with masses M1 = 0.49 kg and M2 = 0.47 kg, are thrown at each other and stick when they collide. Mass 1 has a
malfutka [58]

Answer:

a) p_i=1.568\hat{i}+0.752 \hat{j}

b) v_{fx}=1.668\ m.s^{-1}

c) v_{fy}=0.7999\ m.s^{-1}

Explanation:

Given masses:

m_1=0.49\ kg

m_2=0.47\ kg

Velocity of mass 1, v_1=3.2 \hat{i}\ m.s^{-1}

Velocity of mass 2, v_2=1.6 \hat{j}\ m.s^{-1}

a)

Initial momentum:

p_i=m_1.v_1+m_2.v_2

p_i=0.49\times 3.2 \hat{i}+0.47\times 1.6 \hat{j}

p_i=1.568\hat{i}+0.752 \hat{j}

b)

magnitude of initial momentum:

p_i=\sqrt{1.568^2+0.752 ^2}

p_i=1.739\ kg.m.s^{-1}

From the conservation of momentum:

p_f=p_i

m_f.v_f=1.739

v_f=\frac{1.739}{0.49+0.47}

v_f=1.85\ m.s^{-1} is the magnitude of final velocity.

Direction of final velocity will be in the direction of momentum:

tan\theta=\frac{0.752 }{1.568}

\theta=25.62^{\circ}

\therefore v_{fx}=1.85\ cos25.62^{\circ}

v_{fx}=1.668\ m.s^{-1}

c)

Vertical component of final velocity:

v_{fy}=1.85\ sin 25.62^{\circ}

v_{fy}=0.7999\ m.s^{-1}

6 0
4 years ago
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