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prisoha [69]
3 years ago
15

What is the difference between 1/3=2/6 and 1/6=3/6

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

3/6=1/2 but 3/6= 1/2

fillerfillerfillerfillerfiller

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Si al invertir $60.000 se pierde un 8% ¿A cuánto asciende la pérdida?
svetoff [14.1K]

Trabajando con porcentajes, concluimos que la pérdida es de $4800.

<h3>¿A cuánto asciende la pérdida?</h3>

Sabemos que la inversión inicial es de $60000, y de esta cantidad, se pierde un 8%.

Entonces la pérdida va a ser el 8% de $60000.

Podemos escribir las relaciones:

$60000 = 100%

x = 8%

Queremos resolver esto para x, tomando el cociente entre esas relaciones y resolviendo para x obtenemos:

x = $60000*(8%/100%) = $60000*0.08 = $4800

Así, concluimos que la pérdida es de $4800.

Sí quieres aprender más sobre porcentages:

brainly.com/question/843074

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6 0
2 years ago
What's the answer to this
timofeeve [1]

Answer:

AC ≈ 17.3 , BC ≈ 5.3

Step-by-step explanation:

using the tangent ratio in right triangle ACD

tan51° = \frac{opposite}{adjacent} = \frac{AC}{AD} = \frac{AC}{14} ( multiply both sides by 14 )

14 × tan51° = AC , then

AC ≈ 17.3 ( to the nearest tenth )

using the cosine ratio in right triangle ABC

cos72° = \frac{adjacent}{hypotenuse} = \frac{BC}{AC} = \frac{BC}{17.3} ( multiply both sides by 17.3 )

17.3 × cos72° = BC , then

BC ≈ 5.3 ( to the nearest tenth )

5 0
1 year ago
Determine whether the binomial is a factor of f(x).<br><br> f(x) = x3 + 11x2 + 24x - 36; x - 4
attashe74 [19]
If it is, then f(4) would be equal 0.

f(4)=4^3+11\cdot4^2+24\cdot4-36\\&#10;f(4)=64+11\cdot16+96-36\\&#10;f(4)=124+176\\&#10;f(4)=300\not =0 \Rightarrow \text{ it isn't}
8 0
2 years ago
Let f(x) = cxe−x2 if x ≥ 0 and f(x) = 0 if x &lt; 0.
sergij07 [2.7K]

(a) If <em>f(x)</em> is to be a proper density function, then its integral over the given support must evaulate to 1:

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx = \int_0^\infty cxe^{-x^2}\,\mathrm dx=1

For the integral, substitute <em>u</em> = <em>x</em> ² and d<em>u</em> = 2<em>x</em> d<em>x</em>. Then as <em>x</em> → 0, <em>u</em> → 0; as <em>x</em> → ∞, <em>u</em> → ∞:

\displaystyle\frac12\int_0^\infty ce^{-u}\,\mathrm du=\frac c2\left(\lim_{u\to\infty}(-e^{-u})-(-1)\right)=1

which reduces to

<em>c</em> / 2 (0 + 1) = 1   →   <em>c</em> = 2

(b) Find the probability P(1 < <em>X </em>< 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

\displaystyle\int_1^3 2xe^{-x^2}\,\mathrm dx = \boxed{\frac{e^8-1}{e^9}} \approx 0.3678

5 0
2 years ago
If I charged 30$ a hair cut the whole year how many times would each customer have to come in to get 17,510$
V125BC [204]
You would need to come in 583.6 or 584 times
5 0
2 years ago
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