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yawa3891 [41]
4 years ago
9

Please help me with geometry

Mathematics
1 answer:
spayn [35]4 years ago
3 0
For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points

------------------------------------------------------

For the points (-10,2) and (-2,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-10))^2+(2-2)^2)

d = sqrt((-2+10)^2+(2-2)^2)

d = sqrt((8)^2+(0)^2)

d = sqrt(64+0)

d = sqrt(64)

d = 8

------------------------------------------------------

For the points (-3,-1) and (5,1), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-(-3))^2+(1-(-1))^2)

d = sqrt((5+3)^2+(1+1)^2)

d = sqrt((8)^2+(2)^2)

d = sqrt(64+4)

d = sqrt(68)

------------------------------------------------------

For the points (-3,-2) and (1,3), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-(-3))^2+(3-(-2))^2)

d = sqrt((1+3)^2+(3+2)^2)

d = sqrt((4)^2+(5)^2)

d = sqrt(16+25)

d = sqrt(41)

------------------------------------------------------

For the points (-3,-5) and (-2,-4), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-3))^2+(-4-(-5))^2)

d = sqrt((-2+3)^2+(-4+5)^2)

d = sqrt((1)^2+(1)^2)

d = sqrt(1+1)

d = sqrt(2)

------------------------------------------------------

For the points (0,0) and (5,5), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-0)^2+(5-0)^2)

d = sqrt((5)^2+(5)^2)

d = sqrt(25+25)

d = sqrt(50)

------------------------------------------------------

For the points (1,2) and (1,-10), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-1)^2+(-10-2)^2)

d = sqrt((0)^2+(-12)^2)

d = sqrt(0+144)

d = sqrt(144)

d = 12

------------------------------------------------------

For the points (1,2) and (5,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-1)^2+(2-2)^2)

d = sqrt((4)^2+(0)^2)

d = sqrt(16+0)

d = sqrt(16)

d = 4

------------------------------------------------------

For the points (2,3) and (10,9), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((10-2)^2+(9-3)^2)

d = sqrt((8)^2+(6)^2)

d = sqrt(64+36)

d = sqrt(100)

d = 10

------------------------------------------------------

See the attached image for how the answers match up (take note of the letter labels)

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Anastasy [175]

With f(x)=-10x+9, we have

f(x+h) = -10(x+h) + 9 = -10x + 9 - 10h

Then the difference quotient is

\dfrac{f(x+h)-f(x)}h = \dfrac{(-10x+9-10h)-(-10x+9)}h = \dfrac{-10h}h = -10

since <em>h</em> ≠ 0.

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Allen found 28 pieces of gold Diana found 1880558 pieces of gold how many pieces of gold did they have total
horsena [70]
Well, you need to add 28 to 1880558 which equals 1,880,586.
4 0
3 years ago
Read 2 more answers
Which ordered pair is a solution of the linear system: x+2y=-8 and
andrew-mc [135]

Answer:

option A

A(-2,-3)

Step-by-step explanation:

make y subject of formula

x+2y=-8

2y=-8-x

y=(-8-x)/2

y=-4-x/2

when x=-2

y=-4-(-2)/2

=-4-(-1)

=-4+1

=-3

(-2,-3) is an ordered pair

5 0
3 years ago
Solve the inequality.<br> 2(4+2x)&gt;5x+5<br> oxs-2<br> O X2-2<br> xs3<br> x23
mafiozo [28]

For this case we must resolve the following inequality:

2 (4 + 2x)> 5x + 5

Applying distributive property on the left side of inequality we have:

8 + 4x> 5x + 5

Subtracting 5 from both sides of the inequality:

8-5 + 4x> 5x\\3 + 4x> 5x

Subtracting 4x from both sides of the inequality:

3> 5x-4x\\3> x

Thus, the result is x

Answer:

x

5 0
3 years ago
A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

6 0
2 years ago
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