Answer:
3.8 M
Explanation:
Volume of acid used VA= 57.0 - 37.5 = 19.5 ml
Volume of base used VB= 67.8 - 45.0 = 22.8 ml
Equation of the reaction
2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)
Number of moles of acid NA= 2
Number of moles of base NB= 1
Concentration of acid CA= ???
Concentration of base CB= 1.63 M
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CA= CBVBNA/VANB
CA= 1.63 × 22.8 × 2/ 19.5 × 1
CA= 3.8 M
HENCE THE MOLARITY OF THE ACID IS 3.8 M.
C is correct. right now gravity holds the atmosphere so if there is no gravity then no atmospher
Spillages on a tiled floor, a highly polished floor surface, a damp smooth surface with no mat.
The correct option is (d) To express very large or very small number.
What is the Scientific Notation?
Scientific notation is a way to present numbers that are too large or too small to be easily written in decimal form. The three components of scientific notation are coefficient, base and exponent. The proper format to write a scientific notation is a x 10^b, where a is a number or decimal number and b is the power of 10 to make scientific notation equivalent to original number. When a number between 1 and 10 is multiplied by a power of 10 then the number is expressed in scientific notation. For example, 10000000 can be written as 10⁷, which is the scientific notation and the exponent is positive here. Similarly, for the negative exponent 0.000001 can be can be represented as 10-⁷. Hence, the scientific notation is used to express very large or very small numbers.
Learn more about Scientific Notation here: brainly.com/question/15361382
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Answer: The empirical formula is 
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given:
Mass of Na= 34.5 g
Mass of B= 16.4 g
Mass of O = 48.6 g
Step 1 : convert given masses into moles.
Moles of Na =
Moles of B =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Na = 
For B =
For O =
The ratio of Na: B: O= 1: 1: 2
Hence the empirical formula is
