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3 years ago

Wich formula equation represents the burning of a sulfur to produce sulfur dioxide?

1 answer:

4 0

The balanced reaction that describes the reaction between sulfur<span> and oxygen to </span>produce sulfur dioxide<span> is expressed S(s) + O2 (g) = SO2 (g)</span>

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How many molecules of oxygen are produced when a sample of 38.9 g of water is decomposed by electricity?

statuscvo [17]

Answer:

A) $6.5\times 10^{23}\ \text{molecules}$

Explanation:

m = Mass of water = 38.9

M = Molar mass of water = 18 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

The reaction of electrolysis would be

$2H_2O(l)\rightarrow 2H_2(g)+O_2(g)$

Number of moles of $H_2O$

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{38.9}{18}\ \text{mol}$

From the reaction it can be seen that 2 moles of $H_2O$ gives 1 mole of $O_2$

So, number of moles of $O_2$ produced is

$\dfrac{38.9}{18}\times \dfrac{1}{2}=1.081\ \text{mol}$

Number of molecules

$1.081N_A=1.081\times 6.022\times 10^{23}\\ =6.5\times 10^{23}$

So, $6.5\times 10^{23}\ \text{molecules}$ of oxygen is produced.

8 0

3 years ago

What is the ph of the solution prepared by dissolving 0.927 mol hcl in enough water to make a 150 l aqueous solution?

Brilliant_brown [7]

Answer:

The answer to your question is pH = 2.2

Explanation:

Data

pH = ?

moles of HCl = 0.927

volume = 150 l

Process

1.- Calculate the Molar concentration of HCl

Molarity = moles / volume (L)

Molarity = 0.927 / 150

= 0.00618

2.- Calculate the pH

pH = -log [HCl]

Substitution

pH = -log [0.00618]

Result

pH = 2.2

8 0

3 years ago

Elements on the periodic table are arranged by increasing ?

Galina-37 [17]

They are arranged by their atomic mass.

5 0

3 years ago

I’d appreciate the help! :)

seraphim [82]

Answer: 300g

Explanation:

first we write the given values on top

224L. x

3 NO2 (g) + H2O (l) = 2HNO3 (l) + NO (g)

22.4L 30g

then we form a formula

224L/22.4L= x/30g

224*30/22.4

6720/22.4= 300g

7 0

3 years ago

An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, h

vaieri [72.5K]

Answer:

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

Explanation:

Length of the base = l

Width of the base = w

Height of the pyramid = h

Volume of the pyramid = $V=\frac{1}{3}lwh$

We have:

Rate at which water is filled in cube = $\frac{dV}{dt}= 45 cm^3/s$

Square based pyramid:

l = 6 cm, w = 6 cm, h = 13 cm

Volume of the square based pyramid = V

$V=\frac{1}{3}\times l^2\times h$

$\frac{l}{h}=\frac{6}{13}$

$l=\frac{6h}{13}$

$V=\frac{1}{3}\times (\frac{6h}{13})^2\times h$

$V=\frac{12}{169}h^3$

Differentiating V with respect to dt:

$\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}$

$\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}$

Putting, h = 4 cm

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}$

$=13.20 cm/s$

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

3 0

3 years ago