Answer:
Hydrosulfuric acid will act as limiting reactant.
Explanation:
Given data:
Mass of iron(III) chloride = 3243.0 g
Mass of hydrosulfuric acid = 511.8 g
Limiting reactant = ?
Solution:
Chemical equation:
2FeCl₃ + 3H₂S → Fe₂S₃ + 6HCl
Number of moles of iron(III) chloride:
Number of moles = mass/molar mass
Number of moles = 3243.0 g/ 162.2 g/mol
Number of moles = 20 mol
Number of moles of hydrosulfuric acid:
Number of moles = mass/molar mass
Number of moles = 511.8 g/ 34.1 g/mol
Number of moles = 15 mol
Now we will compare the moles of both reactant with products
FeCl₃ : Fe₂S₃
2 : 1
20 : 1/2 ×20 = 10
FeCl₃ : HCl
2 : 6
20 : 6/2 ×20 = 60
H₂S : Fe₂S₃
3 : 1
15 : 1/3 ×15 = 5
H₂S : HCl
3 : 6
15 : 6/3 ×15 = 30
Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.
Glucose is C6H12O6 and the energy is located in its C-H bonds
Answer:
PH₂ = 0.2 atm
C) About 0.20atm, because H2 comprises 20% of the total number of moles of gas.
Explanation:
To determine the partial pressure of hydrogen gas (H2) in the mixture,
Partial pressure H₂ = Ptotal * xH₂
xH₂ = Mole fraction of H₂ = ∩H₂ / ( ∩H₂ + ∩O₂ + ∩N₂)
xH₂ = 0.01 / (0.01 + 0.015 + 0.025)
xH₂ = 0.01/0.05
xH₂ = 0.2
therefore
PH₂ = pT * xH₂
PH₂ = 1.0 atm * 0.2
PH₂ = 0.2 atm
so the correct option is C) About 0.20atm, because H2 comprises 20% of the total number of moles of gas.
D. there is one atom of sulfur and three atoms of oxygen
