Answer:
20 different kinds of minerals make up 95% of earth's rocks.
<u><em> I hope this helps... please correct me if i'm wrong</em></u>
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Answer:
32.4 K
Explanation:
From the given parameters;
Initial pressure P1= 50.0 mmHg
Initial temperature T1= 540K
Final Temperature T2 = ?????
Final pressure P2=3 mmHg
Now using this relationship;
P1/T1 = P2/T2
We have; P1T2= P2T1
Hence;
T2= P2T1/P1
T2= 3 ×540/50.0
T2= 32.4 K
Answer:
The answer to your question is: 63.5 u
Explanation:
Data Percent Molecular mass
63 Cu 69.2% 62.9296 u
65Cu 30.8% 64.9278 u
Average atomic mass = ?
Formula
Average atomic mass = (0.692 x 62.9296) + (0.308 x 64.9278)
= 43.55 + 19.99
= 63.5 u
<h3>
Answer:</h3>
5.89 × 10^23 molecules of F₂
<h3>
Explanation:</h3>
The equation for the reaction between fluorine (F₂) and ammonia (NH₃) is given by;
5F₂ + 2NH₃ → N₂F₄ + 6 HF
We are given 66.6 g NH₃
We are required to determine the number of fluorine molecules
<h3>Step 1: Moles of Ammonia </h3>
Moles = Mass ÷ Molar mass
Molar mass of ammonia = 17.031 g/mol
Moles of NH₃ = 66.6 g ÷ 17.031 g/mol
= 3.911 moles
<h3>Step 2: Moles of Fluorine </h3>
From the equation 5 moles of Fluorine reacts with 2 moles of ammonia
Therefore,
Moles of fluorine = Moles of Ammonia × 5/2
= 3.911 moles × 5/2
= 9.778 moles
<h3>Step 3: Number of molecules of fluorine </h3>
We know that 1 mole of a compound contains number of molecules equivalent to the Avogadro's number, 6.022 × 10^23 molecules
Therefore;
1 mole of F₂ = 6.022 × 10^23 molecules
Thus,
9.778 moles of F₂ = 9.778 moles × 6.022 × 10^23 molecules/mole
= 5.89 × 10^23 molecules
Therefore, the number of fluorine molecules needed is 5.89 × 10^23 molecules
