1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ryzh [129]
2 years ago
9

Which compound when dissolved in water, will have the lowest freezing point?

Chemistry
1 answer:
Mumz [18]2 years ago
7 0

The compound that will have the lowest freezing point when dissolved in water is 1.0M Mg(NO3)2. That is option 3.

<h3>Comparing the freezing point of solutions</h3>

To compare the freezing points of solution, the total concentration of all the particles when solutes are dissolved in water is determined.

This is an important step to consider because, the greater the concentration of particles, the lower the freezing point will be.

To determine the concentration of all the particles, ionic compounds are alway 2 while covalent compounds are always 1.

  • 1.0M NaCl: This compound is ionic (metal with nonmetal), and will dissolve into 2 parts. The total final concentration is (1m)(2)=2m

  • 1M NaOH: This compound is ionic and will dissolve into 2 parts. The total final concentration is (1m)(2)=2m.

  • 1.0M Mg(NO3)2: This is an ionic compound but contains a polyatomic ions. The total final concentration is 1m(3) = 3m.

  • 2M NH3: This is a covalent compound and will remain in a part. The total final concentration is 2m (1)= 2m.

Therefore, since 1.0M Mg(NO3)2 contains the greater concentration of particles, it has lower freezing point.

Learn more about freezing point here:

brainly.com/question/24314907

You might be interested in
The strength of an atom's attraction for the electrons in a chemical bond is the atom's?
Mazyrski [523]

<span><span>Yes. An element that is highly electronegative pulls more on the electrons in a bond, such as oxygen in H20. This creates a polar bond, where there is a small negative charge on the oxygen, and a small positive charge in between the hydrogens.

</span>Credit goes to "Erin M" answered on yahoo answers a decade ago.
</span>
3 0
3 years ago
Given:
bulgar [2K]

Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ = \frac{59.7}{16} = 3.73125 \ moles

1 mole of methane (CH₄) released 890 kilojoules of energy

3.73125 moles of methane (CH₄) will release ?

= 3.73125 moles x  -890 kJ/mol

= -3320.81 kJ

Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

5 0
3 years ago
A container is filled with hydrogen gas. It has a volume of 4 liters and a pressure of 2 atm. If the pressure of the container i
Dennis_Churaev [7]

Answer:

1.33 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

<em>(P₁V₁) = (P₂V₂)</em>

<em></em>

Knowing that:

V₁  =  4.0 L, P₁ = 2.0 atm,

V₂  =  ??? L, P₂ = 6.0 atm.

  • Applying in the above equation

(P ₁V₁) = (P₂V₂)

<em>∴ V₂ = P ₁V₁/P₂</em> = (2.0 atm)(4.0 L)/(6.0 atm) =<em> 1.33 L.</em>

4 0
3 years ago
What does 3.5 degree of unsaturation tell you?
Kaylis [27]

Answer:

It means the chemical entity is a radical

Explanation:

When we talk of unsaturation, we are referring to the number of pi-bonds in a chemical entity. The alkane, alkene and alkyne organic family are used to as common examples to explain the term unsaturation.

While alkynes have 3 bonds, it must be understood that they have 2 pi bonds only and as such their degree of saturation is two.

In the case of an alkene, there is only one single pi bond and as such the degree of unsaturation is 1.

Now in this case, we have a fractional 0.5 degree of unsaturation alongside the 3 to make a total of 3.5. So what’s the issue here?

The fractional part shows that the chemical entity we are dealing with here is a radical. While the integer 3 shows that there are 3 pi-bonds, the half pi bond remaining tells us that there is a missing electron on one of the atoms involved in the chemical bonding and as such, the 1/2 extra degree of unsaturation tends to tell us this.

Kindly recall that a radical is a chemical entity within which we have at the least an unpaired electron.

5 0
3 years ago
Which of the following is an example of point-source pollution? A. Salt from roads B. Water from a sewage treatment plant C. Fer
ivanzaharov [21]

Answer:

Acid from abandoned mines- D.

7 0
3 years ago
Other questions:
  • Calcule el porcentaje de soluto (%vv) en una disolución preparada con 45,2 mL de ácido nítrico en 205 mL de agua.
    6·1 answer
  • How many total electrons are in a Fe2 ion?
    5·1 answer
  • Why do cars need a cooling system in conjunction with the engine?
    5·1 answer
  • If the concentration of mercury in the water of a polluted lake is 0.250 μg (micrograms) per liter of water, what is the total m
    5·1 answer
  • Given the reaction 2NO2 1/202 N2O5, what is the relationship between the rates of formation of N,0, and disappearance of the two
    8·1 answer
  • Will mark brainliest if answered fast enough.
    6·2 answers
  • How many joules of heat are absorbed when 10.00 grams of water is completely vaporized at its boiling
    13·1 answer
  • Each graph below represents a different type of electromagnetic wave. Which graph most likely illustrates radio waves?
    5·1 answer
  • HELP ASAP PLEASE WILL GIVE 12 points
    10·2 answers
  • What is the functional group of a carboxylic acid?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!