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ryzh [129]
3 years ago
9

Which compound when dissolved in water, will have the lowest freezing point?

Chemistry
1 answer:
Mumz [18]3 years ago
7 0

The compound that will have the lowest freezing point when dissolved in water is 1.0M Mg(NO3)2. That is option 3.

<h3>Comparing the freezing point of solutions</h3>

To compare the freezing points of solution, the total concentration of all the particles when solutes are dissolved in water is determined.

This is an important step to consider because, the greater the concentration of particles, the lower the freezing point will be.

To determine the concentration of all the particles, ionic compounds are alway 2 while covalent compounds are always 1.

  • 1.0M NaCl: This compound is ionic (metal with nonmetal), and will dissolve into 2 parts. The total final concentration is (1m)(2)=2m

  • 1M NaOH: This compound is ionic and will dissolve into 2 parts. The total final concentration is (1m)(2)=2m.

  • 1.0M Mg(NO3)2: This is an ionic compound but contains a polyatomic ions. The total final concentration is 1m(3) = 3m.

  • 2M NH3: This is a covalent compound and will remain in a part. The total final concentration is 2m (1)= 2m.

Therefore, since 1.0M Mg(NO3)2 contains the greater concentration of particles, it has lower freezing point.

Learn more about freezing point here:

brainly.com/question/24314907

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• We obtained the above 10.00-mL solution by diluting a stock solution using a 1.00-mL aliquot and placing it into a 25.00-mL vo
garik1379 [7]

Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) 0.0035 mole

c)  0.166 M

Explanation:

Phosphoric acid is tripotic because it has 3 acidic hydrogen atom surrounding it.

The equation of the reaction is expressed as:

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

1 mole         3 mole

The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b)  if 10.00 mL of a phosphoric acid solution required the addition of 17.50 mL of a 0.200 M NaOH(aq) to reach the endpoint; Then the molarity of the solution is calculated as follows

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

10 ml            17.50 ml

(x) M              0.200 M

Molarity = \frac{0.2*17.5}{1000}

= 0.0035 mole

c) What was the molar concentration of phosphoric acid in the original stock solution?

By stoichiometry, converting moles of NaOH to H₃PO₄; we have

= 0.0035 \ mole \ of NaOH* \frac{1 mole of H_3PO_4}{3 \ mole \ of \ NaOH}

= 0.00166 mole of H₃PO₄

Using the molarity equation to determine the molar concentration of phosphoric acid in the original stock solution; we have:

Molar Concentration =  \frac{mole \ \ of \ soulte }{ Volume \ of \ solution }

Molar Concentration = \frac{0.00166 \ mole \ of \  H_3PO_4 }{10}*1000

Molar Concentration = 0.166 M

∴  the molar concentration of phosphoric acid in the original stock solution = 0.166 M

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What is the overall equation for the covalent bond in H2O . Is it H2 + O2=H2O OR. H2 + O = H2O
AlexFokin [52]

Answer:

The answer is in the photo

Explanation:

I hope that is useful for you :)

4 0
3 years ago
A 1 mol sample of gas has a temperature of 225K, a volume of 3.3L, and a pressure of 500 torr. What would the temperature be if
serg [7]
<h3>Answer:</h3>

78.75 K

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial pressure, P₁ = 500 torr
  • Initial temperature,T₁ = 225 K
  • Initial volume, V₁ = 3.3 L
  • Final volume, V₂ = 2.75 L
  • Final pressure, P₂ = 210 torr                        

We are required to calculate the new temperature, T₂

  • To find the new temperature, T₂ we are going to use the combined gas law;
  • According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

We can calculate the new temperature, T₂;

Rearranging the formula;

T₂ =(P₂V₂T₁) ÷ (P₁V₁)

  = (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)

  = 78.75 K

Therefore, the new volume of the sample is 78.75 K

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