Answer:
the soup will transfer its thermal energy to the spoon
Hope this helps! <u><em>Can you please mark me brainliest? (also can you guys answer my recent questions? thanks ^^ )</em></u>
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Answer:
Explanation:
Lets take
Radius of tube A=r
Length of tube A=L
Radius of tube B= r'
Length of tube B=L'
Given that
L = 2 L'
r= 0.5 r'
r' = 2 r
The pressure across tube given as
The question is incomplete, the complete question is;
A spherical steel ball bearing has a diameter of 2.540cm at 25.00∘C.
(a) What is its diameter when it's temperature is raised to
100∘C?
(b) What temperature change is required to increase its volume by
1.000% ?
Answer:
a) 2.542 cm
b) 303.03°C
Explanation:
Given;
Diameter of the ball= 2.540cm
Initial temperature= 25.0°C
Final temperature= 100.0°C
Percentage increase in volume = 1.000%
Temperature coefficient of expansion for steel =11.0×10^−6/∘C
d2= d1[1 + α(T2-T1)]
d2= 2.540[1 + 11.0×10^−6(100-25)]
d2= 2.540[1 + 8.25×10^-4]
d2= 2.542 cm
From;
%V ×1/100 = V ×3α ×∆T/ V
Substituting values;
1.000 ×1/100= 3× 11.0×10^−6 × ∆T
∆T= 0.01/3× 11.0×10^−6
∆T= 303.03°C
Answer:
<u>144m</u>
Explanation:
The truck is going 24 meters per second, so if 24 meters pass per second, you multiply 24 meters by 6 seconds. And that gives you 144 meters.
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